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lana [24]
4 years ago
11

Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They

determine that a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s. What is the acceleration value of a cart with …a. a mass of M when acted upon by a net force of 2F?b. a mass of 2M when acted upon by a net force of F?c. a mass of 2M when acted upon by a net force of 2F?d. a mass of 4M when acted upon by a net force of 2F?e. a mass of 2M when acted upon by a net force of 4F?
Physics
1 answer:
mamaluj [8]4 years ago
7 0

Answer:

Explanation:

a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s.

F = M x 48

Mass M = F / 48

a )

When force = 2F and mass = M

Acceleration = force / mass

= 2F /F/48

= 48 X 2 = 96 cm/s²

b )

When force = F and mass = 2M

Acceleration = force / mass

= F /2F/48

=  24 cm/s²

c )

When force = 2F and mass = 2M

Acceleration = force / mass

= 2F /2F/48

=  48  cm/s

d )

When force = 2F and mass = 4M

Acceleration = force / mass

= 2F /4F/48

=  24  cm/s

e)

When force = 4F and mass = 2M

Acceleration = force / mass

= 4F / 2M

= 4F / 2 F/48

= 48 x 2

Acceleration  = 96 cm/s²

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\begin{gathered} m_1v_1+m_2v_2=(m_1+m_2)v \\ v=\frac{m_1v_1+m_2v_2}{m_1+m_2} \\ v=\frac{1300\operatorname{kg}\cdot20m/s-900\operatorname{kg}\cdot15m/s}{1300\operatorname{kg}+900\operatorname{kg}} \\ v=5.681m/s \end{gathered}

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holding it and slowly moving forward 2.0m

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Answer:

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Then, the change in momentum of the body is of 32.5 kgm/s (a).

Now, from the impulse-momentum theorem, we know that the change in momentum of a body \Delta p is equal to the impulse I exerted to it. So, the impulse produced by the force equals 32.5 kgm/s (or 32.5 Ns) (b).

Finally, since we know the value of the impulse and the interval of time, we can easily solve for the magnitude of the force:

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