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Ksju [112]
4 years ago
8

How would the composition of an atom change if both the atomic number and mass number each increase by one?

Physics
1 answer:
Softa [21]4 years ago
7 0

If both the atomic number and mass number each increased by one, then ...

-- the atom would have one more proton in its nucleus,

and

-- whenever it was in a neutral state, it would also have one more electron in its cloud.

<em>choice - B</em>

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Determine the mass of the load hanging on the spring with a stiffness of 200 N / m if the extension of the spring is 0.5 cm
dexar [7]

P. E=mgh

P. E=200

200=m x 10 X 0.005

200=m x 0.05

200/0.05=m

4000Kg=m

Hope it helps.......

7 0
4 years ago
A 40-W lightbulb is 1.7 m from a screen. What is the intensity of light incident on the screen? Assume that a lightbulb emits ra
Sonja [21]

Answer:

Intensity, I=1.101\ W/m^2

Explanation:

Power of the light bulb, P  = 40 W

Distance from screen, r = 1.7 m

Let I is the intensity of light incident on the screen. The power acting per unit area is called the intensity of the light. Its formula is given by :

I=\dfrac{P}{A}

I=\dfrac{P}{4\pi r^2}

I=\dfrac{40\ W}{4\pi (1.7\ m)^2}

I=1.101\ W/m^2

So, the intensity of light is 1.101\ W/m^2.

6 0
4 years ago
When a substance changes from one phase to another, which of the following events occurs?
mojhsa [17]

Heat is transferred when a substance changes phases. Substances can be made to change phases by fluctuating the temperature, the pressure, or both. I hope I could help!

5 0
4 years ago
Read 2 more answers
If given both the speed of light in a material and an incident angle. How can you find the refracted angle?
Basile [38]

Answer:

r = Sin^{-1}\left ( \frac{v Sini}{c} \right )

Explanation:

Let the speed of light in vacuum is c and the speed of light in medium is v. Let the angle of incidence is i.

By using the definition of refractive index

refractive index of the medium is given by

n = speed of light in vacuum / speed of light in medium

n = c / v  ..... (1)

Use Snell's law

n = Sin i / Sin r

Where, r be the angle of refraction

From equation (1)

c / v = Sin i / Sin r

Sin r = v Sin i / c

r = Sin^{-1}\left ( \frac{v Sini}{c} \right )

8 0
4 years ago
A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.
enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, KE_{f} = 0.5mv^{2}

a) Using the principle of energy conservation,

KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

7 0
4 years ago
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