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Stels [109]
4 years ago
10

If given both the speed of light in a material and an incident angle. How can you find the refracted angle?

Physics
1 answer:
Basile [38]4 years ago
8 0

Answer:

r = Sin^{-1}\left ( \frac{v Sini}{c} \right )

Explanation:

Let the speed of light in vacuum is c and the speed of light in medium is v. Let the angle of incidence is i.

By using the definition of refractive index

refractive index of the medium is given by

n = speed of light in vacuum / speed of light in medium

n = c / v  ..... (1)

Use Snell's law

n = Sin i / Sin r

Where, r be the angle of refraction

From equation (1)

c / v = Sin i / Sin r

Sin r = v Sin i / c

r = Sin^{-1}\left ( \frac{v Sini}{c} \right )

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densk [106]

Answer:

when the mass of an object is decreased, the acceleration will increase

when mass is increased, acceleration decreases

3 0
3 years ago
Ahsoka pulls a wounded soldier (mass 64 kg) across the ground with a force 18 Newtons. If they have an acceleration of 1.5 m/s2
Kryger [21]

Answer:

0.124

Explanation:

18-(9.81*64)*k=64*1.5

4 0
3 years ago
Read 2 more answers
1. A soccer player kicks a soccer ball towards the goal. If she kicks it with a velocity of 24 m/s at an angle of 31 degrees abo
ruslelena [56]

Answer:

<em>The ball will go as high as 8.46 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object launched at a certain height above the ground and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum height hm can be calculated as follows:

\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}

The soccer ball is kicked at a speed of vo=24 m/s at an angle of θ=31°. Taking the value of g=9.8 m/s^2, then:

\displaystyle h_m=\frac{24^2\cdot \sin^2 31^\circ}{2\cdot 9.8}

\displaystyle h_m=\frac{576\cdot 0.2653}{19.6}

h_m=7.80~m

The ball will go as high as 8.46 m

4 0
3 years ago
Why do wisdom teeth appear later than other types of teeth?
alexandr402 [8]
Hey there!


<span>C A child's jaw is not large enough to hold them.


Hope I helped!

Let me know if you need anything else!

~ Zoe</span>
3 0
3 years ago
A packing crate slides down an inclined ramp at constant velocity. Thus we can deduce thatA) a frictional force is acting on itb
torisob [31]

Answer:

A) a frictional force is acting on it

Explanation:

The crate is sliding down the inclined ramp at constant velocity: constant velocity means zero acceleration, a = 0. According to Newton's second law:

F = ma

this also means that the net force acting along the direction of the slope is zero.

Without frictional force, there would be only one force acting along this direction: the component of the weight of the crane parallel to the slope, acting downward:

W_p = mg sin \theta

where \theta is the angle of the incline. Therefore, the net force along this direction would not be zero. In order to have a net force of zero, there must be another force acting upward on the crate: and the only force that is possibly acting on the crate against its direction of motion is the frictional force, whose magnitude must be equal to W_p, in order to produce a net force of zero (and therefore, a zero acceleration).

8 0
4 years ago
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