Here as we can see the figure the object must have to move with constant speed
So here net force on the object must be zero
so we can say
so here we will have
so there will be 13 N force towards right on this box
Answer:
Explanation:
The hand throwing ball moves on a circular path having radius r = .55 m
mass of ball m = .19 kg
velocity v = 70 mph
= 70 x 1600 / 60 x 60
= 31.11 m /s
centripetal force
= mv² / r
= .19 x 31.11² / .55
= 334.34 N
hi friend the earth spin at 1,000 in meters per hour
I hope it helped you
Answer: The center of gravity is 1.1338 m away from the left side of the barbell
Explanation:
Length of the barbell = 1.90 m
The distance center of gravity from left = x
Mass on the left side = 25 kg
The distance center of gravity from right = 1.90 - x
Mass on the right side = 37 kg
At the balance point:
The center of gravity is 1.1338 m away from the left side of the barbell
Answer:
The velocity of a ball will be "-70.13 m/s".
Explanation:
The given values are:
u = 70 m
t = 0.0 s
g = a = -9.8 m/s²
s = -1 m
v = ?
As we know,
The equation of motion will be:
⇒
On substituting the estimated values, we get
⇒
⇒
⇒
⇒
⇒
⇒
In downward direction, it will be:
⇒