Answer:
0.1349
Step-by-step explanation:
Given that:
Sample size, n = 500
20% of 500 ; 0.2 * 500 = 100
p = 0.18 ; n = 500 ; 1 - p = 0.82
P(x ≥ 100) ;
Using the binomial probability relation :
P(x =x) = nCx * p(x)^x * (1 - p)^(n - x
P(x ≥ 100) = 500C100 * 0.18^100 * 0.82^400
P(x ≥ 100) = 0.1349
Answer:
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The answer is -6 sorry could not explain because have to go somewhere hope it helped
