Answer:
22 m/s
Explanation:
PEf +KEf =PE0 +KE0 →PE0 −PEf =KEf
−mgΔy= 1 mv2 →v= −2gΔy = −2(9.8 m/s2)(−25 m)=22 m/s
It is called a warm front when a warm air mass moves into an area where a cold air mass is located based on the blanked sentence above. A warm front is a condition where a warm air mass is replacing a cold air in a place. The character of a warm front condition is an increasing in temperature of a place which is caused by the moving warm air mass<span>.</span>
Answer:
1.52s
Explanation:
Given parameters:
Acceleration = 63m/s²
Final velocity = 96m/s
Unknown:
Time taken = ?
Solution:
To solve this problem, we use one of the kinematics equation:
v = u + at
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
So;
96 = 0 + 63t
t = 1.52s
B. An image that is larger than the object and is in front of the mirror
