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Assoli18 [71]
3 years ago
14

a car company claims that its car can accelerate from rest to a speed of 28.0 m/s in 20.0 s. find the average acceleration of th

e car
Physics
1 answer:
elixir [45]3 years ago
5 0

tje average acceleration of the car is

\frac{28}{20}  = 1.4

the average acceleration of the car is 1.4 m/s

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The sound waves from a noisy jet travel from the air into water. Which property of the wave will not change?​
notka56 [123]

The frequency of the wave will not change. Since the change in medium doesn't affect the source of the waves, the frequency of those waves do not change.

Hope this helps! :)

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3 years ago
A scientist is trying to predict the regions of the world most likely to see a decrease in natural resources from population cha
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<u><em>Developed countries will see a decrease in natural resources, because their population will decrease.</em></u>

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3 years ago
Read 2 more answers
A long ramp made of cast iron is sloped at a constant angle θ = 52.0∘ above the horizontal. Small blocks, each with mass 0.42 kg
dezoksy [38]

Answer:

For cast iron we have

h = 0.92 m

For copper

h = 1.05 m

For Lead

h = 1.23 m

For Zinc

h = 2.43 m

Explanation:

As we know that final speed of the block is calculated by work energy theorem

W_f + W_g = \frac{1}{2}mv^2

now we have

-\mu_k mg cos\theta(\frac{h}{sin\theta}) + mgh = \frac{1}{2}mv^2

now we have

v^2 = 2gh - 2\mu_k g h cot\theta

v = \sqrt{2gh(1 - \mu_k cot\theta)}

For cast iron we have

4 = \sqrt{2(9.81)(h)(1 - 0.15cot52)}

h = 0.92 m

For copper

4 = \sqrt{2(9.81)(h)(1 - 0.29cot52)}

h = 1.05 m

For Lead

4 = \sqrt{2(9.81)(h)(1 - 0.43cot52)}

h = 1.23 m

For Zinc

4 = \sqrt{2(9.81)(h)(1 - 0.85cot52)}

h = 2.43 m

4 0
3 years ago
In any electromagnetic wave,
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C.half the energy is carried by the electric field and half is carried by the magnetic field.
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3 years ago
If 36 grams of water is to be heated from 24.0°C to 48°C to make a cup of tea, how much heat must be added? The specific heat of
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We will have the following:

\begin{gathered} Q=mc\Delta T\Rightarrow Q=(36)(4.18)(48-24) \\  \\ \Rightarrow Q=3611.52 \end{gathered}

So, the heat to add is 3611.52 Joules.

3 0
1 year ago
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