Which statement is correct about a vacuole?

A man stands at the midpoint between two speakers that are broadcasting an amplified static hiss uniformly in all directions. Th

Illusion [34]

Answer:

Explanation:

The power of each of the speakers is 0.535 W. At a distance d intensity of sound can be found by the following formula

Intensity of sound = Power / 4π d²

= .535 / 4 x 3.14 x (27.3/2)²

= 2.286 x 10⁻⁴ J m⁻² s⁻¹

Intensity of sound due to other source = 5.715 x 10⁻⁵J m⁻² s⁻¹

Total intensity = 2 x 2.286 x 10⁻⁴J m⁻² s⁻¹

= 4.57 x 10⁻⁴J m⁻² s⁻¹

b ) In this case, man is standing at distances 18.15 m and 9.15 m from the sources .

The total intensity of sound reaching him is as follows

0.535 / (4 π x18.15² ) + 0.535 / (4 π x9.15² )

= 1.293 x 10⁻⁴ + 5.087 x 10⁻⁴

= 6.38 x 10⁻⁴J m⁻² s⁻¹

5 0

3 years ago

An iron vat is 11 m long at room temperature (20°C). How much longer is it when it contains boiling water at 1 atm pressure?

RoseWind [281]

Answer:

The change in length is 0.01056 m.

Explanation:

Given that,

Length = 11 m

Temperature = 20°C

Pressure = 1 atm

Boiling temperature = 100°C

We need to calculate the length

Using formula of change in linear expansion

$\dfrac{\Delta L}{L}=\alpha_{l}\Delta T$

$\Delta L=L\times\alpha_{l}\times(T_{f}-T_{i})$

Put the value into the formula

$\Delta L=11\times12\times10^{-6}\times(100-20)$

$\Delta L=11\times12\times10^{-6}\times80$

$\Delta L=0.01056\ m$

Hence, The change in length is 0.01056 m.

5 0

4 years ago

A 0.0434-m3 container is initially evacuated. Then, 4.19 g of water is placed in the container, and, after some time, all of the

adell [148]

Answer:

P =18760.5 Pa

Explanation:

Given that

Volume ,V= 0.0434 m³

Mass ,m= 4.19 g = 0.00419 kg

T= 417 K

If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation

Ideal gas equation P V = m R T

p=Pressure ,V = Volume ,m =mass

T=Temperature ,R=Universal gas constant

Now by putting the values

P V = m R T

For water R= 0.466 KJ/kgK

P x 0.0434 = 0.00419 x 0.466 x 417

P =18.7605 KPa

P =18760.5 Pa

Therefore the answer is 18760.5 Pa

6 0

4 years ago

What is the chemical formula for copper (I) sulfide? A) CuS B) CuS2 C) Cu2S D) Cu2S3

Ganezh [65]

This problem can be solved by using oxidation states. The oxidation state is based on the electrons an atom loses or gain, or appears to use when forming compounds.To find the formula for Copper (I) Sulfide, we have to first consider the individual ions that come together to form it. Copper (I) is an ion of copper that has a charge of +1, i.e $Cu^{+}$ . Sulfur is an element in group 6 of the periodic table. The sulfur ion has a charge of -2, i.e $S^{2-}$ . To form Copper (I) Sulfide, which is electrically neutral, we need 2 Copper (I) ions and 1 sulfur ion.