Answer:
6/5 hours
Step-by-step explanation:
<u>GIVEN :-</u>
Lets say ,
- Pump A takes 2 hours to fill the tank alone
- Pump B takes 3 hours to fill the tank alone
<u>TO FIND :-</u>
- Time taken by both pumps to fill the tank when used together
<u>PROCEDURE :-</u>
In 2 hours , Pump A fills the whole tank.
⇒ In 1 hour , Pump A will fill 1/2 part of tank. (By using Unitary method)
In 3 hours , Pump B fills the whole tank.
⇒ In 1 hour , Pump B will fill 1/3 part of tank. (By using Unitary method)
In 1 hour , when both pumps will be used together , they will fill =
(Part of tank filled by A in 1hr) + (Part of tank filled by B in 1hr)
⇒ 
part of tank
5/6 part of tank will be filled by both the pumps in = 1 hour.
Using unitary method, multiplying both the sides with 6/5 -
⇒ 5/6 × 6/5 part of tank will be filled by both the pumps in = 1 × 6/5 hours
⇒ Total tank (or 1 whole tank) will be filled by both the pumps in = 6/5 hours
∴ Both the pumps will take 6/5 hour to fill the tank , when used together.
Answer: y int: (0,9) x int: (3,0)
Step-by-step explanation:
In slope intercept form, the equation is y=-3x+9. In the formula y=mx+b, we know b is the y intercept, so our y int. is 9. To find our x intercept, we set y=0. So, 0=-3x+9=>3x=9=>x=3
Every 56 seconds, the radioactive substance is divided in half.
224 / 56 = 4
We need to cut the substance in half 4 times.
896 / 2 = 448
448 / 2 = 224
224 / 2 = 112
112 / 2 = 56
After 224 seconds, there will be 56 grams of the radioactive substance left over
<u>Answer:</u>
Point Form:
(−5,1)
Equation Form:
x=−5, y=1
<u>Step-by-step explanation:</u>
Solve for the first variable in one of the equations, then substitute the result into the other equation.
1. x=5y−10
2. 20y−30=−10
3. y=1
4. x=−5