Answer:
A = 2.36m/s
B = 3.71m/s²
C = 29.61m/s2
Explanation:
First, we convert the diameter of the ride from ft to m
10ft = 3m
Speed of the rider is the
v = circumference of the circle divided by time of rotation
v = [2π(D/2)]/T
v = [2π(3/2)]/4
v = 3π/4
v = 2.36m/s
Radial acceleration can also be found as a = v²/r
Where v = speed of the rider
r = radius of the ride
a = 2.36²/1.5
a = 3.71m/s²
If the time of revolution is halved, then radial acceleration is
A = 4π²R/T²
A = (4 * π² * 3)/2²
A = 118.44/4
A = 29.61m/s²
<span>
E = mc^2 = 8.152*10^-30 *(3.00 *10^8)^2 = 7.336 *10^-13 J. </span>
B. Asteroids have a nearly circular orbit.
Answer:
freqiency=velocity/wavelength
ief=20/2000=0.01hz
The best choice would be C. Keep one end of the rope tied to the post and have all six boys tug on the other end.
Reason:
A is not correct since in the first case which is B, untying the rope from the post and have 3 boys on each end of it tug, will provide equal or a near equal amount of tension since the boys are all within the same strength, however there can be variables that will affect the tension.
That means B would be true according to A, and then for C, having all six boys pull on the other end of the rope would provide greater tension, since if 3 boys of the same strength range can't break the rope when its tied to the fence, we add the other 3 boys of the same strength.
However, if 3 boys are on each end of the rope and of the same strength then the rope will not break since there is an equal amount of net force exerted on the rope.
We know that the fence can withstand the strength of 3 boys but if we add the other 3 boys then it could provide us with a different outcome.
3B < F
3B(2) ≥ F
So, therefore, our best choice would be C since A and B is incorrect.
