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3 years ago

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One particle has a charge of -1.87 x 10-9 C, while another particle has a charge of -1.10 x 10-9 C. If the two particles are sep

arated by 0.05, what is the electromagnetic force between them? The equation for Coulomb's law is F = k9192, and the constant, k, equals 9.00 x 10-9 Nm2/C2 pa 2
A. 3.70 x 10-7 N
B. -7.41 x 10-6N
C. -3.70 x 10-7 N
D. 7.41 x 10-6 N

1 answer:

bogdanovich [222]3 years ago

5 0

Answer:D 7.41 x 10-6 N

Explanation: AP*X

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