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igor_vitrenko [27]
3 years ago
5

A boxer pushes on a 25 kg heavy bag which is attached to the ceiling until it makes an angle of 36 degrees to the vertical. How

much force must the boxer exert on the bag?
Physics
1 answer:
umka2103 [35]3 years ago
6 0

Answer:

198.20 N

Explanation:

Given that,

Mass of a heavy bag, m = 25 kg

The bag is attached to the ceiling until it makes an angle of 36 degrees to the vertical.

We need to find the force must the boxer exert on the bag. The force acting on the bag is given by :

F=mg\cos\theta\\\\=25\times 9.8\times \cos(36)\\\\=198.20\ N

So, the required force is 198.20 N.

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Some bacteria are propelled by biological motors that spin hair-like flagella. A typical bacterial motor turning at a constant a
Anestetic [448]

Answer:

(a) \omega=1.41*10^3\frac{rad}{s}

(b) t=4.46*10^{-3}s

Explanation:

The angular speed is a measure of the rotation speed. Thus, It is defined as the angle rotated by a unit of time:

\omega=\frac{\theta}{t}(1)

The arc length in a circle is given by:

s=r\theta\\\theta=\frac{s}{r}(2)

s is the length of an arc of the circle, so v=\frac{s}{t}.

Replacing (2) in (1):

\omega=\frac{s}{t}\frac{1}{r}\\\omega=\frac{v}{r}

a) Now, we calculate the angular speed:

\omega=\frac{2.21*10^{-5}\frac{m}{s}}{1.57*10^{-8}m}\\\omega=1.41*10^3\frac{rad}{s}

b) We use (1) to calculate the time it takes to make one revolution, which means that \theta is 2\pi.

\omega=\frac{\theta}{t}\\t=\frac{\theta}{\omega}\\t=\frac{2\pi}{1.41*10^3\frac{rad}{s}}\\t=4.46*10^{-3}s

8 0
3 years ago
Is the fuel filter considered to be part of the cars engine?
nikdorinn [45]
Yes it is concidered to be apart of the cars engine. 
3 0
4 years ago
When the forces acting moving body are balanced the net force becomes zero. As a result the body will:
WINSTONCH [101]

Answer:

<h2>a</h2><h2> move with an increasing velocity</h2>
5 0
3 years ago
An object has a velocity of 8 m/s and a kinetic energy of 480 J. What is the mass of the object? (Formula: ) KE=1/2mv squared
Julli [10]

Answer:15kg

Explanation:

kinetic energy=ke=480J

Velocity=v=8m/s

Mass=m

Ke=0.5 x m x v x v

480=0.5 x m x 8 x 8

480=32m

Divide both sides by 32

480/32=32m/32

15=m

Mass=15kg

5 0
3 years ago
You are given three pieces of wire that have different shapes (dimensions). You connect each piece of wire separately to a batte
VikaD [51]

Answer:

R_3 < R_1 < R_2

Explanation:

The resistance of a wire is given by:

R=\frac{\rho L}{A}

where

\rho is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

1) The first wire has length L and cross-sectional area A. So, its resistance is:

R_1=\frac{\rho L}{A}

2) The second wire has length twice the first one: 2L, and same thickness, A. So its resistance is

R_2=\frac{2\rho L}{A}

3) The third wire has length L (as the first one), but twice cross sectional area, 2A. So, its resistance is

R_3=\frac{\rho L}{2A}

By comparing the three expressions, we find

R_3 < R_1 < R_2

So, this is the ranking of the wire from most current (least resistance) to least current (most resistance).

5 0
3 years ago
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