The answer is acceleration.
Acceleration is the rate at which velocity changes over time. The relationship between acceleration and velocity is presented in the formula:
a = Δv/Δt
The SI unit of acceleration is m/s² derived as following:
a = Δv/Δt [ = ] (m/s)/s = m/s * s = m/s²
Answer:
30°
Explanation:
The angle between the normal and the vertical is the same as the angle between the incline and the horizontal. We can show this with geometry.
Answer:
a. TRUE
Explanation:
When a satellite is launched to orbit around earth, it has to produce its own artificial gravity by performing rotations. The frequency of this rotation is given by the following formula:
f = √[ac/4πR²]
where,
f = frequency
ac = centripetal acceleration
R = Radius of the satellite
Therefore, it is clear from this formula that the frequency of rotation of the satellite is independent of its height above the surface of earth. So, the correct option is:
<u>a. TRUE</u>
Answer:
Black body.
Explanation:
It's the property of the blackbody that it emits the maximum amount of radiation at a given temperature and also absorbs the radiation which incident upon it.
Velocity vs. time graph shows the acceleration as a slope whereas displacement vs. time graph shows the velocity as a slope. So, the given statement is false.
Answer: Option B
<u>Explanation:</u>
To understand the acceleration graphically, consider the x axis of the graph as the run and the y axis as the velocity rise. Now, as we all know that,

We can estimate this through the graph. let's draw the motion of an object with time if it's velocity is changing in every second by 4 m/s. Now if we draw this on graph, we will see that there is a slope between the two corresponding values of time and velocity. This slope defines the acceleration for the object with time.
Now, in the same way, if we draw a distance and time graph respective to the y and x axis; we'll get a slope which defines the velocity of the object i.e. change in distance with time.
Hence, with a velocity vs time graph, we get the slope for acceleration whereas with the distance and time graph, we get the slope for velocity. So both the cases, we see there is no velocity slope on an acceleration and time graph. Hence the statement is false.