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Black-spotted skin coat as camouflage while stalking prey.
Survival = avoiding predators or capturing prey successfully
Answer:
d) Wind
Explanation:
Secondary energy is energy produced by converting energy available in its natural state in the environment. Hence Wind is a primary source not a secondary source
Answer:
2.47 m
Explanation:
Let's calculate first the time it takes for the ball to cover the horizontal distance that separates the starting point from the crossbar of d = 52 m.
The horizontal velocity of the ball is constant:
![v_x = v cos \theta = (25)(cos 35.9^{\circ})=20.3 m/s](https://tex.z-dn.net/?f=v_x%20%3D%20v%20cos%20%5Ctheta%20%3D%20%2825%29%28cos%2035.9%5E%7B%5Ccirc%7D%29%3D20.3%20m%2Fs)
and the time taken to cover the horizontal distance d is
![t=\frac{d}{v_x}=\frac{52}{20.3}=2.56 s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7Bv_x%7D%3D%5Cfrac%7B52%7D%7B20.3%7D%3D2.56%20s)
So this is the time the ball takes to reach the horizontal position of the crossbar.
The vertical position of the ball at time t is given by
![y=u_y t - \frac{1}{2}gt^2](https://tex.z-dn.net/?f=y%3Du_y%20t%20-%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
where
is the initial vertical velocity
g = 9.8 m/s^2 is the acceleration of gravity
And substituting t = 2.56 s, we find the vertical position of the ball when it is above the crossbar:
![y=(14.7)(2.56) - \frac{1}{2}(9.8)(2.56)^2=5.52 m](https://tex.z-dn.net/?f=y%3D%2814.7%29%282.56%29%20-%20%5Cfrac%7B1%7D%7B2%7D%289.8%29%282.56%29%5E2%3D5.52%20m)
The height of the crossbar is h = 3.05 m, so the ball passes
![h' = 5.52- 3.05 = 2.47 m](https://tex.z-dn.net/?f=h%27%20%3D%205.52-%203.05%20%3D%202.47%20m)
above the crossbar.
The linear speed of the pepperoni is 0.628 m/s. Its direction is tangential to the circle.
We know that;
v = rω
r = radius of the piece = 10 cm or 0.1 m
ω = angular velocity
We have to convert 60 revolutions per minute to radians per second
1 rev/min = 0.10472 rad/s
60 revolutions per minute = 60 rev/min × 0.10472 rad/s/1 rev/min
= 6.28 rad/s
v = 0.1 m × 6.28 rad/s
v = 0.628 m/s
The direction of this velocity is tangential to the circle.
Learn more: brainly.com/question/4612545