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Deffense [45]
3 years ago
13

An irrigation channel has a rectangular cross section of 1.5 ft deep x 11 ft wide on the input side. On the far end of the chann

el, the channel expands to 6 ft wide while maintaining the same depth. If the water flowing into the channel has a speed of 30 ft/sec, calculate the velocity of the water flow on the far end of the channel.
Physics
1 answer:
garik1379 [7]3 years ago
5 0

Answer:

55 ft/s

Explanation:

A₁ = Area of rectangular cross-section at input side = 1.5 x 11 = 16.5 ft²

A₂ = Area of rectangular cross-section at far end = 1.5 x 6 = 9 ft²

v₁ = speed of water at the input side of channel = 30 ft/s

v₂ = speed of water at the input side of channel = ?

Using equation of continuity

A₁ v₁ = A₂ v₂

(16.5) (30) = (9) v₂

v₂ = 55 ft/s

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Select the correct term to complete each sentence. If you the wavelength, the electromagnetic radiation energy will double. The
Andrews [41]

Answer:

A) If you halve the wavelength, the electromagnetic radiation energy will double.

B) The energy of the electromagnetic radiation will halve if you halve the wavenumber.

C) When the frequency of the light is doubled, its energy will double.

Explanation:

The function for the light frequency is given as

The energy supplied to each electron is doubled by halving the wavelength, nearly doubling its kinetic energy by two after it is free from the metal. It is important to remember that for a given period of time, the number of electrons ejected will remain constant.

Cheers

5 0
3 years ago
You need to know the height of a tower, but darkness obscures the ceiling. You note that a pendulum extending from the ceiling a
Sonja [21]

Answer:

L=55.9m

Explanation:

The equation for the period of a simple pendulum is:

T=2\pi\sqrt{\frac{L}{g}}

In our case what we know is the period and the acceleration of gravity, and we need to know the length of the pendulum, so we can write:

L=(\frac{T}{2\pi})^2g

Which for our values is:

L=(\frac{15s}{2\pi})^2(9.81m/s^2)=55.9m

6 0
3 years ago
A 1.45 kg 1.45 kg falcon catches a 0.415 kg 0.415 kg dove from behind in midair. What is their velocity after impact if the falc
jarptica [38.1K]

Answer: The velocity is 21.5m/s

Explanation:

Let's call:

M1 and V1 as the mass and velocity of the falcon:

M1 = 1.45kg

V1 = 26.5m/s

M2 and V2 as the mass and velocity of the dove:

M2 = 0.415kg

V2 = 4.35m/s

Where both velocities are positive because both animals move in the same direction.

We can think that the interaction between both animals is a perfectly inelastic collision, because afther the interaction they move as one. Then, we have that the final velocity of both animals togheter is:

V = (V1*M1 + V2*M2)/(M1 + M2)

V = (1.45kg*26.5m/s + 0.415kg*4.35m/s)/(1.45kg + 0.415kg) = 21.5m/s

7 0
3 years ago
Multiple-Concept Example 6 reviews the concepts that play a role in this problem. A diver springs upward with an initial speed o
adell [148]

Answer:

Part a)

v_f = 7.99 m/s

Part b)

y = 3.25 m

Explanation:

Part a)

Since the diver is moving under gravity

so here its acceleration due to gravity will be uniform throughout the motion

so here we will have

v_f^2 - v_i^2 = 2 a y

here we have

v_i = 2.22 m/s

y = -3 m

v_f^2 - (2.22)^2 = 2(-9.81)(-3)

v_f = 7.99 m/s

Part b)

at highest point of his motion the final speed will be zero

so we will have

v_f^2 - v_i^2 = 2 a (\Delta y)

0 - 2.22^2 = 2(-9.81)(y - 3)

y = 3.25 m

7 0
3 years ago
In the diagram below, point A is southwest of point B. Jaleh walks for 400 seconds along path 1, going from point A to point B.
timama [110]

Answer:

C

Explanation:

velocity = displacement (m) / change of time (s)

velocity = (400 + 300) / (100 + 400)

velocity = 1.4 m/s

4 0
2 years ago
Read 2 more answers
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