An irrigation channel has a rectangular cross section of 1.5 ft deep x 11 ft wide on the input side. On the far end of the chann
el, the channel expands to 6 ft wide while maintaining the same depth. If the water flowing into the channel has a speed of 30 ft/sec, calculate the velocity of the water flow on the far end of the channel.
The turns ratio is equal to the voltage ratio. Let n1 and n2 be the primary and secondary turns. Then 5850V/120V=n1/n2 48.75=2680/n2 n2=2680/48.75 n2=55