Answer:
Correct answer: Cf = tan 33° = 0.649 (I guess you meant degrees and not minutes)
Explanation:
The horizontal component of the object's weight equals to the force of friction and the object is just about to slide.
The horizontal component of the object's weight is Qh = mg sin 33°
The force of friction is Ffr = Cf · Qv = Cf · mg cos 33° , where Cf is the coefficient of static friction and Qv vertical component of the object's weight
Qh - Ffr = 0 => Qh = Ffr => mg sin 33° = Cf mg cos 33°
we divide both sides of the equation by mg and get:
Cf · cos 33° = sin 33° => Cf = sin 33° / cos 33° = tan 33° = 0.649
Cf = 0.649 the weight of the object is unnecessary data
God is with you!!!
Answer:
Explanation:
1) for A+B: a²+b²-2abcos(π-α);
2) for A-B: a²+b²-2abcos(α);
3) according to the condition (A+B):(A-B)=n, then
Answer:
5.88×10⁸ W
Explanation:
Power = change in energy / time
P = mgh / t
P = (m/t) gh
P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)
P = 5.88×10⁸ W
Answer:
6.36 105 J
Explanation:
In calorimetry all the energy given to a system is converted to heat and the equation for heat is
Q = m ΔT
The temperature can be in degrees Celsius or Kelvin since the interval between them is the same, substitute and calculate
Q = 1.9 4186 (373-293)
Q = 6.36 105 J
This heat equals the energy supplied