The magnetic field in a region of space is specified by its x, y, and z components which are respectively Bx = 0.136 T, By = 0.1
1 answer:
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Answer:
(a) T = 0.412s
(b) f = 2.42Hz
(c) w = 15.25 rad/s
(d) k = 86.75N/m
(e) vmax = 5.03 m/s
Explanation:
Given information:
m: mass of the block = 0.373kg
A: amplitude of oscillation = 22cm = 0.22m
T: period of oscillation = 0.412s
(a) The period is the time of one complete oscillation = 0.412s
The period is 0.412s
(b) The frequency is calculated by using the following formula:
The frequency is 2.42 Hz
(c) The angular frequency is:
The angular frequency is 15.25 rad/s
(d) The spring constant is calculated by solving the following equation for k:
The spring constant is 86.75N/m
(e) The maximum speed is:
(f) The maximum force applied by the spring if for the maximum elongation, that is, the amplitude:
The maximum force that the spring exerts on the block is 17.35N
Answer:
t = 300 seconds
Explanation:
Given that,
The power output of the motor, P = 1.5 kW
Energy transferred = 450 000 J
Power is given by work done per unit time. So,
So, it will take 300 seconds for the motor.