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Radda [10]
4 years ago
10

--The sum of two numbers is 33. One number is 2 times as large as the other. What are the numbers?​

Mathematics
2 answers:
frozen [14]4 years ago
4 0

Answer:

11 and 22

Step-by-step explanation:

Let x be the first number

the second number is twice the first one so it's 2x

The equation is

  • 2x+x =33
  • 3x = 33             divide by 3 in each side
  • x = 33/3
  • x= 11

so the first number is 11 and the second one 22 (11*2)

alex41 [277]4 years ago
4 0

Answer:

2x + x =33

Step-by-step explanation:

let the number be ''x''

the other number is 2 times as large, so it is 2x

their sum is 33

  • 2x + x = 33

find the value of x

2x + x = 33

3x = 33

3x= 33  

x = 33/3   (divide 3 on both sides )

x = 11

apply the value of x

2 (11) + 11 = 33

22 + 11 = 33

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Where does the helix r(t) = cos(πt), sin(πt), t intersect the paraboloid z = x2 + y2? (x, y, z) = What is the angle of intersect
Colt1911 [192]

Answer:

Intersection at (-1, 0, 1).

Angle 0.6 radians

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The <em>tangent vector</em> to the helix in t=1 is

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r'(t) = (-πsin(πt), πcos(πt), 1), hence

r'(1) = (0, -π, 1)

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\bf z=x^2+y^2

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\bf (\frac{\partial f}{\partial x}(-1,0),\frac{\partial f}{\partial y}(-1,0),-1)

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\bf f(x,y)=x^2+y^2

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\bf \frac{\partial f}{\partial x}=2x,\;\frac{\partial f}{\partial y}=2y

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(-2,0,-1)

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\bf \theta=arccos(0.8038)=0.6371\;radians

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