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4 years ago

Solve systems of linear equations.NEED ASAP y=5x-8 y=-6x+3

1 answer:

5 0

Your first solution▶y - 5(x) = -8
Your second solution▶y + 6x = 3

Your graphic organizer ▶-5(x) + (y) = -8;
6(x) + (y) = 3

y-intercept in the 2nd solution▶(y)= -6(x) + 3

y-intercept in the 1st solution▶-6(x)+3 - 5(x) = -8 ; - 11(x) = -11
(we get the '11x' from the 6 + 5)

x-intercept in the 1st solution▶11(x) = 11
Does 11(1) =11
▶Answer is yes, so the x-intercept is 1
➡x-intercept: 1

y-intercept should be coming up soon!

(y) = -6(1)+3
⬆ ⬆
-6 + 3 = -3
So, the y-intercept is -3

y-intercept: -3

x-intercept: 1

~in other words~

x-intercept: 1

y-intercept: -3

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3 years ago

Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of f :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of g :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where n is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So f has a minimum of -7 and a maximum of 299.

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3 years ago

Please help with areas

Softa [21]

Answer:

Step-by-step explanation:

7) The formula for determining the area of a parallelogram is expressed as

Area = base × height.

Length of base = Area/height

Therefore,

Length of base = 7/2 = 3.5 feet

8) The formula for determining the area of a trapezoid is expressed as

Area = 1/2(a + b)h

Where

a and b are the length of the bases

h is the height. Therefore

21 = 1/2(2 + 4)h

21 = 3h

h = 21/3 = 7 inches

9) Area = base × height.

Height = Area/Length of base

Height = 28/14 = 2 inches

10) a and b are 10 inches each.

Area = 1/2(a + b)h

Therefore,

35 = 1/2(10 + 10)h

35 = 10h

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3 years ago

Find an equation of the plane with x-intercept a, y-intercept b, and z-intercept c. What is the distance between the origin and

Elenna [48]

Answer:

The equation is:

(1/a)x + (1/b)y + (1/c)z = 1

Step-by-step explanation:

The direction vector between the points (a, 0, 0) and (0, b, 0) is given as:

<0 - a, b - 0, 0 - 0>

<-a, b, 0> .....................(1)

The direction vector between (0, 0, c) and (0, b, 0) is given as:

<0 - 0, b - 0, 0 - c>

= <0, b, -c> .....................(2)

To obtain the direction vector that is normal to the surface of the plane, we take the cross product of (1) and (2).

Doing this, we have:

<-a, b, 0> × <0, b, -c> = <-bc, -ac, -ab>

To find the scalar equation of the plane we can use any of the points that we know. Using (0, b, 0), we have:

(-bc)x + (-ac)y + (-ab)z = (-bc)0 + (-ac)b + (-ab)0

(bc)x + (ac)y + (ab)z = (ac)b

Dividing both sides by abc, we have:

(1/a)x + (1/b)y + (1/c)z = 1

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