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3 years ago

3,842.58 rounded to the nearest tenth

1 answer:

8 0

The tenths place is where the 5 is
To round, look at the number before it which is a 8
Since 8 is above 5 you round up
So the answer is 3,842.6

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Find the value of x

kodGreya [7K]

Answer:

Last Option

Step-by-step explanation:

We have a triangle and we know its three sides.

We want to find one of your anguos. Then we use the cosine theorem.

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx$

Where

$c = 14\\a = 11\\b = 19$

Now we solve for x from the equation

$c ^ 2 = a ^ 2 + b ^ 2 -2abcosx\\\\\\14^2 = 11^2 + 19^2 -2(11)(19)cosx\\\\14^2 -11^2 -19^2 = 2(11)(19)cosx\\\\-286=2(11)(19)cosx\\\\cosx = \frac{-286}{2(11)(19)}\\\\x = arcos(\frac{-286}{2(11)(19)})\\\\x = 46.8\°$

6 0

3 years ago

Read 2 more answers

18=3(1+12 x)-5(10x+11)

madreJ [45]

18=3+36x-50x-55

18=3-14x-55

18=-14x-52

70=-14x

x=-5

6 0

3 years ago

Another name for the x axis

aalyn [17]

Answer:

axis of abscissas

Step-by-step explanation:

8 0

3 years ago

Use the given graph of f to state the value of each quantity, if it exists. (If an answer does not exist, enter DNE.)

alex41 [277]

Answer:

Hence the answer is given as follows,

Step-by-step explanation:

Graph of y = f(x) given,

(a) $\lim_{x\rightarrow 2^{-}}f(x)=3$

(b) $\lim_{x\rightarrow 2^{+}}f(x)=1$

(c) $\lim_{x\rightarrow 2}f(x)= DNE \left \{ \therefore \lim_{x\rightarrow 2^{-}} f(x)\neq \lim_{x\rightarrow 2^{+}}f(x) \right.$

(d) $f(2)=3$

(e) $\lim_{x\rightarrow 4}f(x) = 4$

(f) $f(4)= DNE.$ { Hole in graph}

Hence solved.

3 0

3 years ago

In a jar, there is a green, a blue, and a red marble. You draw (with replacement) a marble from the jar until you get the green

denpristay [2]

Answer:

The value is $P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}$

Step-by-step explanation:

From question we are told that

The number of types of marbles present jar is n = 3

Generally the probability of drawing a green marble is

$P(g) = \frac{1}{3}$

Generally the probability of drawing a marble that is not green is

$P(g') = 1 - \frac{1}{3} = \frac{2}{3}$

From the question we are told that there will be continuous drawing of marbles from the jar (in such a way that after each marble is drawn it is being replaced) until a green marble drawn

Let m be the number of times marbles has been drawn when a green marble was gotten

it then means that for m - 1 times the marbles where drawn a green marble was not obtain.

Generally the probability drawing m times is mathematically is mathematically represented as

$P( X = m ) = (P(g'))^{m-1 } * P(g)$

=> $P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}$

7 0

3 years ago