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Deffense [45]
3 years ago
8

What is the name of the state when electrons absorb energy and move to a higher energy level?

Chemistry
1 answer:
murzikaleks [220]3 years ago
3 0

Answer:

Excited state is the name of the state when electrons absorb energy and move to a higher energy level.

Explanation:

You might be interested in
What is extrapolation?
bixtya [17]

Answer:

A. Predicting data that fall beyond a known data point

Explanation:

Extrapolating is unreliable because you are predicting data outside of the data range - anything could happen for the data to stop following the trend or pattern

8 0
3 years ago
How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?
vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

7 0
3 years ago
What is the theoretical yield of methanol (CH3OH) when 12.0 grams of H2 is mixed with 74.5 grams of CO? CO + 2H2 CH3OH
AlladinOne [14]
1) We need to convert 12.0 g of H2 into moles of H2, and <span> 74.5 grams of CO into moles of CO
</span><span>Molar mass of H2:    M(H2) = 2*1.0= 2.0 g/mol
Molar mass of CO:   M(CO) = 12.0 +16.0 = 28.0 g/mol

</span>12.0 g  H2 * 1 mol/2.0 g = 6.0 mol H2
74.5 g CO * 1 mol/28.0 g = 2.66 mol CO

<span>2) Now we can use reaction to find out what substance will react completely, and what will be leftover. 

                                  CO       +         2H2   ------->      CH3OH  
                                 1 mol              2 mol
given                        2.66 mol          6 mol (excess)

How much
we need  CO?           3 mol              6 mol

We see that H2 will be leftover, because for 6 moles H2  we need 3 moles CO, but we have only 2.66 mol  CO.
So, CO will react completely, and we are going to use CO to find  the mass of CH3OH.

3)                              </span>CO       +         2H2   ------->      CH3OH  
                                 1 mol                                        1 mol
                                2.66 mol                                    2.66 mol

4) We have 2.66 mol CH3OH
Molar mass CH3OH : M(CH3OH) = 12.0 +  4*1.0 + 16.0 = 32.0 g/mol

2.66 mol CH3OH * 32.0 g CH3OH/ 1 mol CH3OH =  85.12 g CH3OH
<span>
Answer is </span>D) 85.12 grams.
3 0
3 years ago
Is a covalent bond the same as an atomic compound? Please explain why and if not, please explain the difference.
dezoksy [38]
In an ionic bond, one atom essentially donate an electron to stabilize the other atom. A molecule bond is made when two or more atoms form a chemical bond, linking them together. The two types of bonds are ionic bonds and covalent bonds.
6 0
3 years ago
Select the reagents you would use to synthesize the compounds below from benzene. Use the minimum number of steps.
iris [78.8K]

Answer:

A

C

Explanation:

For the reaction of m-bromonitrobenzene from benzene first, we need to carry out the nitration of benzene utilizing HNO3, H2SO4.  

Bromination of nitrobenzene with Br2, FeBr3 outfits m-bromonitrobenzene in light of the fact that nitro group is meta coordinating for electrophile. The mechanism activity for the reaction is shown in the image below.

5 0
3 years ago
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