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nadya68 [22]
2 years ago
7

Augh senpai gimmie your but

Chemistry
1 answer:
LenaWriter [7]2 years ago
6 0
I don’t understand the question
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Is rubbing alcohol polar, non-polar, or ionic?
Karolina [17]

Answer: Rubbing alcohol molecules have a polar and nonpolar part, which means they are able to form hydrogen bonds with water and therefore able to mix with it.

Explanation:

7 0
2 years ago
How many calories of heat are necessary to raise the temperature of 319.5 g of water from 35.7 °C
rjkz [21]

20600Cal              

Explanation:

Given parameters:

Mass of water = 319.5g

Initial temperature = 35.7°C

Final temperature = 100°C

Unknown:

Calories needed to heat the water = ?

Solution:

The calories is the amount of heat added to the water. This can be determined using;

     H  =   m  c Ф

c  = specific heat capacity of water = 4.186J/g°C

   H is the amount of heat

    Ф is the change in temperature

    H = m c (Ф₂ - Ф₁)

    H = 319.5 x 4.186 x (100 - 35.7) = 85996.56J

Now;

     1kilocalorie = 4184J

     

85996.56J to kCal; \frac{85996.56}{4184}   = 20.6kCal  = 20600Cal

               

learn more:

Specific heat brainly.com/question/3032746

#learnwithBrainly

6 0
3 years ago
H2SO4 +HI → __ H2S+12 +H2O balance the equation
Citrus2011 [14]

Answer:

H2SO4 + 8HI → H2S + 4I2 + 4H2O

3 0
2 years ago
What is a disadvantage of a series circuit?
Digiron [165]
The answer is B

If one circuit fails, it is most likely that all the components in the circuit will fail.
3 0
2 years ago
There is a 30g of be-11 it has a half-life of about 14 seconds how much will be left in 28 seconds
Lelu [443]

There will be 7.5 g of Be-11 remaining after 28 s.

If 14 s = 1 half-life, 28 s = 2 half-lives.

After the first half-life, ½ of the Be-11 (15 g) will disappear, and 15 g will remain.

After the second half-life, ½ of the 15 g (7.5 g) will disappear, and 7.5 g will remain.

In symbols,

<em>N</em> = <em>N</em>₀(½)^<em>n</em>

where

<em>n</em> = the number of half-lives

<em>N</em>₀ = the original amount

<em>N</em> = the amount remaining after <em>n</em> half-lives

6 0
2 years ago
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