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Sliva [168]
3 years ago
10

Write the following numbers in scientific notation: a) 0.0006730 b)50000.0 c)0.000003010 d) 132.40 e)2232​

Chemistry
2 answers:
zimovet [89]3 years ago
8 0

Answer:

a) 0.0006730:6.73×10^-4

b)50000.0 =5×10^4

c)0.000003010 =3.01×10^-6

d) 132.40 =1.32×10²

e)2232=2.232×10³

Firdavs [7]3 years ago
3 0

Answer:

a)6.730×10⁻⁴

b)5×10⁴

c)3.010×10⁻⁶

d)1.3240×10²

e)2.232×10³

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Answer:

a) Percentage by mass of carbon: 18.3%

   Percentage by mass of hydrogen: 0.77%

b)  Percentage by mass of chlorine: 80.37%

c) Molecular formula: C_{2} H Cl_{3}

Explanation:

Firstly, the mass of carbon must be determined by using a conversion factor:

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The same process is used to calculate the amount of hydrogen:

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The percentage by mass of carbon and hydrogen are calculated as follows:

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From the precipation data it is possible obtain the amount of chlorine present in the compound:

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Assuming that we have 100g of the compound, it is possible to determine the number of moles of each element in the compound:

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80.37gCl*\frac{1molCl}{35.45g Cl} = 2.27mol Cl

Dividing each of the quantities above by the smallest (0.77mol), the  subscripts in a tentative formula would be

C=\frac{1.52}{0.77} = 1.97 ≈ 2

H = \frac{0.77}{0.77} = 1

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The empirical formula for the compound is:

C_{2} H Cl_{3}

The mass of this empirical formula is:

mass of C + mass of H + mass of Cl= 24g +1+ 106.35 =131.35g

This mass matches with the molar mass, which means that the supscript in the molecular formula are the same of the empirical one.

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