Gases diffuse most efficiently across A) thin,moist selectivly permeable membrane. B) thin, moist impermeable membrane. C) thick
2 answers:
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Answer:101.105⁰c
Explanation:
Answer: 160 ml
Explanation:
The expression used will be :
where,
= concentration of Ist alcohol solution= 10%
= concentration of 2nd alcohol solution= 55%
= volume of Ist alcohol solution = 200 ml
= volume of 2nd alcohol solution= v ml
= concentration of resulting alcohol solution= 30%
= volume of resulting alcohol solution= (v+200) ml
Now put all the given values in the above law, we get the volume of added.
By solving the terms, we get :
Therefore, the volume of 55% mixture needed to be added to obtain the desired solution is 160 ml.
It equals 0.005 but plz mark this as the brainliest question plz
