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4 years ago

5

An atom that undergoes radioactive decay and has a large nucleus most likely contains

2 answers:

aksik [14]4 years ago

5 0

<span>The answer is: more protons than neutrons The stability of the nucleus is based on the ratio of neutrons and protons present in the nucleus. if the number of protons is equal to the number neutrons then the nucleus is stable but in case the number of protons is more than the number neutrons or the other way round the nucleus to gain stability starts interconversion of neutron to proton or electron or decreases proton numbers. In case of nucleus containing high energy, the nucleus releases it. Such nuclei which release energy to gain stability are called radioactive nuclei and the phenomenon is called radioactivity.</span>

tankabanditka [31]4 years ago

4 0

More protons than neutrons

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What atoms must be present in a molecule for it to be considered organic?

dalvyx [7]

Atoms of Carbon along with hydrogen bonded to the carbons in the molecule are 2 main elements for the molecule to be organic.

3 0

4 years ago

How do you detect which material is going to be positively charged or negatively charged?

I am Lyosha [343]

Answer:

If a material gains electrons, its going to be Negatively charged

If a material loses electrons, its gonna be positively charged.

Explanation:

Why?

This is because electrons are negative subatomic particles

6 0

3 years ago

The reaction of hydrogen sulfide(g) with oxygen(g) to form water(l) and sulfur dioxide(g) proceeds as follows: 2H2S(g) 3O2(g)2H2

Aleks [24]

Answer: The value of $\Delta H$ is 1118 .

Explanation:

To calculate the number of moles, we use the equation:

$\text{Moles of solute}=\frac{\text{given mass}}{\text{molar mass}}$

$\text{Moles of} H_2S}=\frac{9.82g}{34.1g/mol}=0.288mol$

The balanced chemical reaction is:

$2H_2S(g)+3O_2(g)\rightarrow 2H_2O(l)+2SO_2(g)$

Given :

Energy released when 0.288 mole of $H_2S$ is reacted = 161 kJ

Thus Energy released when 2 moles of $H_2S$ is reacted = $\frac{161}{0.288}\times 2=1118kJ$

Thus the value of $\Delta H$ is 1118.

3 0

3 years ago

A gas occupies a volume of 0.7 L at 10.1 kPa. What volume will the gas occupy at 101 kPa?

Nataly [62]

Answer:

7L

Explanation:

Divide 101 by 10.1(kPa) and you get 10.

10 x .7 = 7

4 0

2 years ago

A material has an ASTM grain size number of 7. Determine the magnification, if the number of grains per square inch observed is:

Luden [163]

Answer:

A) M = 100X

B) M = 36X

C) M = 178.88X

Explanation:

Given data:

ASTM grain size number 7

a) total grain per inch^2 - 64 grain/inch^2

we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

therefore we have

$64 = 2^{7-1}(\frac{100}{M})^2$

solving for M we get

M = 100 X

B) total grain per inch^2 = 500 grain/inch^2

we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

therefore we have $500 = 2^{7-1}(\frac{100}{M})^2$

solving for M we get

M = 36 X

C) Total grain per inch^2 = 20 grain/inch^2

we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

therefore we have $20 = 2^{7-1}(\frac{100}{M})^2$

solving for M we get

M = 178.88 X

8 0

3 years ago