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Vika [28.1K]
3 years ago
5

An atom that undergoes radioactive decay and has a large nucleus most likely contains

Chemistry
2 answers:
aksik [14]3 years ago
5 0
<span>The answer is: more protons than neutrons The stability of the nucleus is based on the ratio of neutrons and protons present in the nucleus. if the number of protons is equal to the number neutrons then the nucleus is stable but in case the number of protons is more than the number neutrons or the other way round the nucleus to gain stability starts interconversion of neutron to proton or electron or decreases proton numbers. In case of nucleus containing high energy, the nucleus releases it. Such nuclei which release energy to gain stability are called radioactive nuclei and the phenomenon is called radioactivity.</span>
tankabanditka [31]3 years ago
4 0
More protons than neutrons
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This type of equation is a what reaction?
sergey [27]

Answer:

Decomposition

Explanation:

H2CO3 Breaks down to H2O and CO2

5 0
3 years ago
How are atoms grouped on the periodic table
alex41 [277]
The periodic table<span> organizes the chemical elements according to the number of protons that each has in its atomic nucleus.</span>
3 0
3 years ago
Which of the followings are true 1,3-BPG? A. It regulates Hb B. It contains a high-energy bond C. It contains two ester bonds D.
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Answer:

D. It contains a phosphate with higher phosphoryl transfer potential than ATP

Explanation:

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7 0
3 years ago
A laboratory analysis of a 100 g sample finds it is composed of 1.8 g hydrogen, 56.1 g sulfur, and 42.1 g oxygen. What is its em
Neporo4naja [7]

Answer: The empirical formula is H_2S_2O_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mas of H = 1.8 g

Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles

Mass of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = \frac{1.8}{1.8}=1

For S = \frac{1.8}{1.8}=1

For O =\frac{2.6}{1.8}=1.5

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is H_2S_2O_3

7 0
3 years ago
A sample of silver has a mass of 21 grams
ad-work [718]

Answer:

density \: of \: the \: silver =  \frac{mass}{volume}  =  \frac{21}{2} \\   = 10.5 \: gram {(cm)}^{ - 3}

<h2>10.5 gram(cm)^-3 is the right answer.</h2>

8 0
3 years ago
Read 2 more answers
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