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bagirrra123 [75]
3 years ago
15

I NEED HELP QUICK RIGHT NOW

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0
The first photo are for questions 3-5

The second photo are for 6-8

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18. Jace has $2.15 in nickels and dimes. If he has 7 more nickels than dimes, how many of each kind of coin does he have?
Gwar [14]

There are 12 dimes and 19 nickels

<h3>The required simultaneous equations</h3>

Since Jace has $2.15 in nickels and dimes.

We know that 1 nickel = $ 0.05 and 1 dime = $0.10

Let

  • n = number of nickels and
  • n' = number of dimes

We have that

0.05n + 0.10n' = 2.15   (1)

Since he has 7 more nickels than dimes, we have that

n = n' + 7       (2)

<h3>The number of dimes</h3>

Substituting equation (2) into (1), we have

0.05n + 0.10n' = 2.15   (1)

0.05(n' + 7) + 0.10n' = 2.15  

0.05n' + 0.35 + 0.10n' = 2.15  

0.15n' + 0.35 = 2.15  

0.15n' = 2.15 - 0.35

0.15n' = 1.8

n' = 1.8/0.15

n' = 12

<h3>The number of nickels, </h3>

Since the number of nickels, n = n' + 7

Substituting n = 12 into the equation, we have

n = n' + 7

n = 12 + 7

n = 19

So, there are 12 dimes and 19 nickels

Learn more about simultaneous equations here:

brainly.com/question/21654746

4 0
2 years ago
HELPP PLEASE What is the value of x in the diagram below?
Westkost [7]

Answer:

x = 3

Step-by-step explanation:

The triangles are similar, using ratios

x            8

------ = -----------

18              48

We can use cross products to solve

48x  = 8*18

48x = 144

Divide each side by 48

48x/48 = 144/48

x =3

8 0
3 years ago
(x+3)=6<br> Solve the equation
kvv77 [185]

You do x + 3 which equals 3x and then divide it by 6 which equals 2

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3 years ago
In the number 36,802 if the 8 was replaced with a 2 would the value increase or decrease
stepan [7]

Answer:

decrease

Step-by-step explanation:

4 0
3 years ago
Graph the image of the given triangle under a dilation with a scale factor of –4 and center of dilation (0,0).
Dvinal [7]

Step-by-step explanation:

Hey there!

The coordinates of a triangle are;

  • A (1,2)
  • B (1,-2)
  • C (-2,-2)
  • Scale factor = -4 and centre at (0,0)

Now, We have;

P(x,y)----------- P'(kx, ky)

<u>Keep</u><u> </u><u>formula</u><u>;</u>

<u>A</u><u>(</u><u>1</u><u>,</u><u>2</u><u>)</u><u>----------</u><u> </u><u>A'</u><u>(</u><u>-4</u><u>×</u><u>1</u><u> </u><u>,</u><u>-4</u><u>×</u><u>2</u><u>)</u>

= A'(-4, -8)

B(1,-2)------------- B'(-4,8)

C(-2,-2)-------------C'(8,8)

[ <u>The</u><u> </u><u>A'</u><u> </u><u>should</u><u> </u><u>be</u><u> </u><u>kept</u><u> </u><u>in</u><u> </u><u>(</u><u>-4</u><u>,</u><u>-</u><u>8</u><u>)</u><u>.</u><u> </u><u>There</u><u> </u><u>was</u><u> </u><u>no</u><u> </u><u>place</u><u> </u><u>in</u><u> </u><u>this</u><u> </u><u>graph</u><u> </u><u>so</u><u>,</u><u> </u><u>i</u><u> </u><u>kept</u><u> </u><u>it</u><u> </u><u>just</u><u> </u><u>below</u><u> </u><u>-7</u><u>.</u><u> </u><u>Please</u><u> </u><u>while</u><u> </u><u>plotting</u><u> </u><u>remember</u><u> </u><u>to</u><u> </u><u>keep</u><u> </u><u>it</u><u> </u><u>on</u><u> </u><u>"</u><u>-8"</u><u>.</u><u>]</u>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
4 years ago
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