The value of a=9,b=3 and c=1
Step-by-step explanation:
The graph shown is for function f(x)
The given function is f(x)=
Table says,
X Y
-2 a
1 b
0 c
1 (1/3)
2 (1/9)
To find value of a:
From table, for output value a, input value, x=(-2)
we can write f(-2)=a
Therefore,
f(x)=
f(-2)=
a=
a=
a=9
To find value of b:
From table, for output value a, input value, x=(-1)
we can write f(-1)=b
Therefore,
f(x)=
f(-1)=
b=
b=
b=3
To find value of c:
From table, for output value a, input value, x=(0)
we can write f(0)=c
Therefore,
f(x)=
f(0)=
c=
c=1
65/3=21 with 2 leftover
(2/3)/3 or 2/3•1/3 = 2/9
so either they didn’t get to share or each got 2/9 of the leftovers
Answer:
D) 0.35
Step-by-step explanation:
The table gives the area between z=0 and the given magnitude of z. That is, the area between z = 0 and z = -0.6 is 0.23, as found in the 0.6 column of the table. Similarly, the area between z = 0 and z = 0.3 is 0.12, as found in the 0.3 column of the table.
The area between z = -0.6 and z = +0.3 is the sum of these areas:
p(-.6<z<.3) = 0.23 +0.12 = 0.35
9 because it's the gcf (greatest common factor)