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3 years ago

Write an equation in point-slope form for each line (If possible please show work)

Mathematics

1 answer:

UkoKoshka [18]3 years ago

7 0

Answer:

y - 1 = -1(x + 1)

Step-by-step explanation:

I found where these points were on the graph. The slope of the line is -1. I used the x and y values from the points and the slope to make the equation above.

Take the y-value of one point and subtract it from y. Do the same thing to the x-values.

By the way, I used the second point to make the equation, but either point could have been used.

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10 POINTS AND BRAINLIEST Please answer all 3 questions attached correctly.

lana66690 [7]

Answer:

#1. Identity #2. 0 #3. No solution

Step-by-step explanation:

#1.

5y + 2 = (1/2)(10y+4)

5y + 2 = 5y + 2

This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).

#2.

0.5b + 4 = 2(b+2)

0.5b + 4 = 2b + 4

0.5 b - 2b = 0

b = 0

#3.

-3x + 5 = -3x + 10

This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.

5 0

3 years ago

2x^16-32x^4 what is the completely factored form

marysya [2.9K]

Answer:

Step-by-step explanation:

$~~~2x^{16} - 32x^4\\\\ = 2x^4(x^{12} -16)\\\\=2x^4\left[(x^6)^2 - 4^2 \right]\\\\=2x^4(x^6 -4)(x^6 +4)~~~~~~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=2x^4\left[(x^3)^2 - 2^2\right] (x^6 +4)\\\\=2x^4(x^3 -2)(x^3 +2)(x^6 +4)$

4 0

1 year ago

What is the value of y in this system of equations: 3x + y = 9 y = –4x + 10 ?

Ahat [919]

3x + y = 9 (I)
y = –4x + 10 (II)
------------------------
 $\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.$

Pass the incognito "4x" to the first term, changing the signal when changing sides.
-------------------------
simplify by (-1)
 $\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.$ 

-------------------------
 $\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right. 
$

-------------------------
 $\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.$ 

-----------
 $\boxed{x = 1}$ 

Substitute in equation (I) to find the value of "Y".

3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3
$\boxed{y = 6}$

Answer:
$\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}$

6 0

3 years ago

Just answer 3 and 4 you don’t need to show your work just answers please!

ad-work [718]

#3.) 48 pieces of ribbon
#3.) this week they cost $112

8 0

3 years ago

susie reads 4 pages in 5 minutes at this rate how many pages will she have read in 35 minutes set up a Proportion and solve

belka [17]

Answer:

Step-by-step explanation:

i did this on a hw equation