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3 years ago

Hi please help me with this question

Chemistry

1 answer:

tatiyna3 years ago

3 0

Answer:

G : pent-2-ene

H : H2o

I : pent-1-ene

Explanation:

The OH would combine with H from H-O4SH

Then the O attached to the carbon would get detached taking the electrons with it, leaving carbon an positively charged.

The OH now combined with H-O4SH would take the H away from the acid forming H2O and (O4SH)-

The negative ion of (O4SH)- would then take the H from positively charged C forming the sulphuric acid back. It does not take the electrons with it*

Which is why the carbon can then form a double bond with the excess electron (2). the major product would be pent-2-ene and minor would be pent-1-ene.

This is because pent-2-ene is more stable than pent-1-ene. (Due to secondary carbon and primary carbon factor)

This is the whole backstage story though.

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Jobisdone [24]

Answer:

$a=4.213cm$

$r=1.490x10^{-8}cm$

Explanation:

Hola.

En este caso, para calcular la longitud (a) de una cara de celda unitaria, consideramos la siguiente ecuación:

$\rho =\frac{#at*M}{a^3N_A}$

En la que consideramos el número de átomos por celda (4 para FCC), la masa molar (40.3 g/mol para MgO) y el número de avogadro para obtener:

$3.581g/mol = \frac{4atom/celda*40.3g/mol}{a^3*6.02x10^{23}atom/mol}$

Despejando para a, obtenemos:

$a^3 = \frac{4atom/celda*40.3g/mol}{3.581g/cm^3*6.02x10^{23}atom/mol}\\\\a=\sqrt[3]{7.478cm^3} \\\\a=4.213cm$

Finalmente, el radio lo calculamos como:

$r=\frac{\sqrt{2}*a}{4}=\frac{\sqrt{2}*4.213x10^{-8}cm}{4}\\\\r=1.490x10^{-8}cm$

¡Saludos!

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