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3 years ago

At which temperature does the motion of atoms and molecules stop?

Physics

1 answer:

Scorpion4ik [409]3 years ago

4 0

Answer:

0 Kelvin

Explanation:

Atoms in absolute temperature get approximatelly motionless since 0 Kelvin is -273 degrees Celcius. The kinetic energy of atoms/particles in matter has the possible lowest value ( almost zero), so that there is nothing colder than 0 Kelvin.

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A 1.0-kilogram object moving east with a velocity of 10 meters per second collides with a 0.50-kilogram object that is at rest.

NeTakaya

Answer:

10kg m/s

Explanation:

We can use the conversation of momentum for this question. Essentially the momentum before and after the crash will remain the same. We can use the formula P = mv to solve.

P = 1 * 10

P = 10kg m/s

Best of Luck!

3 0

3 years ago

What does the half life for a radioactive material mean?

marissa [1.9K]

Half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive

6 0

3 years ago

Due to an influx of wild animals, you need to enclose your garden. You have 500 feet of fencing and will enclose the garden on t

elena55 [62]

Answer:

so length of the fence is 250 feet

Explanation:

Given data

fencing (L) = 500 feet

enclose the garden = 3 sides

to find out

length of the fence

solution

we consider barn length x and width y

so we say x +2y = 500 ........1

we want to maximize length i.e xy = f

so we say

df/dx = ƛ × dL/dx

y = ƛ × 1

and

df/dy = ƛ × df/dy

x = ƛ × 2

from equation 1 we can say

2 ƛ + 2 ƛ = 500

so ƛ = 500/4 = 125

so that x = 2× 125 , y = 125

so x = 250 , y = 125

so length of the fence is 250 feet

3 0

4 years ago

What is the mathematical relationship between voltage (V), resistance (R), and current (I)? Express your answer as an equation:

Lemur [1.5K]

V=IR
I=V/R
R=V/I
these are the realations of voltage ,resistance , and current .

3 0

3 years ago

Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =

Sloan [31]

Answer:

The current is $I = 8.9 *10^{-5} \ A$

Explanation:

From the question we are told that

The radius is $r = 3.17 \ mm = 3.17 *10^{-3} \ m$

The current density is $J = c\cdot r^2 = 9.00*10^{6} \ A/m^4 \cdot r^2$

The distance we are considering is $r = 0.5 R = 0.001585$

Generally current density is mathematically represented as

$J = \frac{I}{A }$

Where A is the cross-sectional area represented as

$A = \pi r^2$

=> $J = \frac{I}{\pi r^2 }$

=> $I = J * (\pi r^2 )$

Now the change in current per unit length is mathematically evaluated as

$dI = 2 J * \pi r dr$

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

$I = 2\pi \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr$

$I = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr$

$I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.$

$I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]$

substituting values

$I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]$

$I = 8.9 *10^{-5} \ A$

5 0

4 years ago