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Sholpan [36]
3 years ago
11

At which temperature does the motion of atoms and molecules stop?

Physics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer:

0 Kelvin

Explanation:

Atoms in absolute temperature get approximatelly motionless since 0 Kelvin is -273 degrees Celcius. The kinetic energy of atoms/particles in matter has the possible lowest value ( almost zero), so that there is nothing colder than 0 Kelvin.

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The fulcrum is the
olga_2 [115]

Answer:

point of support on which a lever rotates.

Explanation:

The fulcrum is the point of support on which a lever rotates. Fulcrum is a pivotal part of simple machines.

The fulcrum provides the platform for a lever to torque.

  • The force that opposes motion by the applied force is termed the frictional force.
  • Friction is a force that opposes motion.
  • The stored energy of an object is its potential energy.
  • The potential energy is the energy due to the position of a body.
  • The distance an object moves when doing work is termed its displacement.
6 0
3 years ago
What type of energy is the sum of an object’s potential and kinetic energy?
nikklg [1K]

Answer: its mechanical energy

Explanation:

8 0
3 years ago
Richard is driving home to visit his parents. 135{\rm mi} of the trip are on the interstate highway where the speed limit is 65{
nydimaria [60]

Answer:

time spent = 0.2276

Explanation:

given data

distance = 135 mi

usual speed = 65 mph

today speed = 73 mph

solution

we get here time that is express as

time = \frac{distance}{speed}    ...................1

usual time = \frac{135}{65}  = 2.0769 h

today time = \frac{135}{73} = 1.8493 h

so we get here time spent as

time spent = 2.0769 h - 1.8493 h

time spent = 0.2276

6 0
3 years ago
How much energy is required to raise the temperature of 5g of air by 10°C?
Alex777 [14]
You need to know the specific heat capacity of air.
Then energy needed = 0.005 x sp.heat.cap x 10
4 0
3 years ago
How to solve 30(a)<br><br> Give solution asap.
expeople1 [14]

Answer:

They will not meet

h-hX=1.2*g*t²

hX=v0*t-(1/2*g*t²)

Explanation:

fall h=1/2*g*t²

elevation time if v0=20 m/s  te=v0/g=20 m/s /9.81 m/s²=2.0387s

hmax=v0²/(2*g)=(400 m²/s²)/19.62 m/s²2=20.387 m

free fall

t=2.0387s yields hX=1/2*g*t²=20.387 m

h-hX=200m - 20.387 m=179,613 m.

so, the second body has not enough initianoal speed to reach a meeting point

5 0
3 years ago
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