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katrin [286]
3 years ago
8

A constant force N acts on an object as it moves along a straight-line path. If the object’s displacement is m, what is the work

done by this given force?
Physics
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

Work = N x m

Explanation:

W=Fxd

Work equals force times the distance (displacement).

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A:True It is good too monitor your grades because you can keep track of your grades and pinpoint your weaknesses.

Explanation:

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Two 5000-kg passenger cars roll without friction (one at 1 m/s, the other at 2 m/s) toward one another on a level track. They co
balu736 [363]

The combined momentum of the passengers is 5000 kgm/s.

<h3>Combined momentum of the passenger</h3>

The combined momentum of the passengers is calculated as follows;

P = mv1 + mv2

where;

  • m is mass of the passengers
  • v1 is velocity of the first passenger
  • v2 is velocity of the second passenger

P = m(v1 + v2)

P = 5000(-1 + 2)

P = 5000 kgm/s

Thus, the combined momentum of the passengers is 5000 kgm/s.

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Describe 4 common workplace practices that are risk factors for injury
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High task repitition, forceful exertions, repetitive or sustained awkward posture
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3 years ago
If two objects are moving at the same speed, and Object 1 has four times as much mass as Object 2, how much momentum does Object
Margaret [11]
The answer is  number 1
7 0
3 years ago
A particle moves along the x axis. It is intially at the position 0.270 m, moving with velocity 0.140 m/s and acceleration -0.32
Nataliya [291]

Answer:

The position of the particle is -2.34 m.

Explanation:

Hi there!

The equation of position of a particle moving in a straight line with constant acceleration is the following:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the particle at a time t:

x0 = initial position.

v0 = initial velocity.

t = time

a = acceleration

We have the following information:

x0 = 0.270 m

v0 = 0.140 m/s

a = -0.320 m/s²

t = 4.50 s  (In the question, where it says "4.50 m/s^2" it should say "4.50 s". I have looked on the web and have confirmed it).

Then, we have all the needed data to calculate the position of the particle:

x = x0 + v0 · t + 1/2 · a · t²

x = 0.270 m + 0.140 m/s · 4.50 s - 1/2 · 0.320 m/s² · (4.50 s)²

x = -2.34 m

The position of the particle is -2.34 m.

6 0
3 years ago
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