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4 years ago

8

A constant force N acts on an object as it moves along a straight-line path. If the object’s displacement is m, what is the work

done by this given force?

1 answer:

JulijaS [17]4 years ago

7 0

Answer:

Work = N x m

Explanation:

W=Fxd

Work equals force times the distance (displacement).

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Find the force of a 600 kg car experiences accelerating from 10 km/hr to 35 km/hr in 3 seconds?

NNADVOKAT [17]

Given,
m=600 kg
u=10 km/hr
v=35 km/hr
t= 3 sec
a=?
F=?

To find a:
u=10 km/hr=5/18*10=25/6=4.16m/s
v=35 km/hr=5/18*35=175/18=9.72m/s
t=3 sec

Now we have,
u=4.16m/s
v=9.72m/s
t=3 sec

To find acceleration:
a=(v-u)/t
a=( 9.72-4.16)/3
a=5.56/3
a=1.85m/s^2

To find F:
m=600 kg
a=1.85 m/s^2

F=ma
F=600*1.85
F=1110N

Therefore, F=1110N

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4 years ago

A bird can fly 25 km/hr. How long does it take to fly 10 km?

Svetradugi [14.3K]

Answer:

25 minutes

Explanation:

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3 years ago

NEED HELP ASAP!!!! DUE in 5 MINS!!!!<br><br>$20 in the ratio 1 to 4 WILL GIVE BRAINLIEST

rusak2 [61]

Answer:

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3 years ago

Read 2 more answers

Some car manufacturers claim that their vehicles could climb a slope of 42 ∘. For this to be possible, what must be the minimum

Paladinen [302]

Answer:

D. 0.9

Explanation:

Calculating minimum coefficient of static friction, we first resolve the forces (normal and frictional) acting on the vehicle at an angle to the horizontal into their x and y components. After this, we can now substitute the values of x and y components into equation of static friction. Diagrammatic illustration is attached.

Resolving into x component:

∑ $F_{x} = F_{s} - mgsin\alpha =0$

$F_{s} = mgsin\alpha$ ------(1)

Resolving into y component:

∑ $F_{y} = F_{n} - mgcos\alpha =0$

$F_{n} = mgcos\alpha$ ------(2)

Static frictional force, $F_{s} \leq$ μ $F_{n}$ ------(3)

substituting $F_{s}$ from equation (1) and $F_{n}$ from equation (2) into equation (3)

$mgsin\alpha \leq$ μ $mgcos\alpha$

$sin\alpha \leq$ μ $cos\alpha$

μ $\geq \frac {sin\alpha}{cos\alpha}$

μ $\geq tan\alpha$

The angle the vehicles make with the horizontal α = 42°

μ ≥ tan 42°

μ ≥ 0.9

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3 years ago

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Explanation:

Now, looking down the solenoid tube determine what direction is the winding. If clockwise in relation to the positive wire then is the south pole, if anti-clockwise then is the north pole. So, to summarize the magnetic south pole is always clockwise in relation to the positive wire.

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