Given,
m=600 kg
u=10 km/hr
v=35 km/hr
t= 3 sec
a=?
F=?
To find a:
u=10 km/hr=5/18*10=25/6=4.16m/s
v=35 km/hr=5/18*35=175/18=9.72m/s
t=3 sec
Now we have,
u=4.16m/s
v=9.72m/s
t=3 sec
To find acceleration:
a=(v-u)/t
a=( 9.72-4.16)/3
a=5.56/3
a=1.85m/s^2
To find F:
m=600 kg
a=1.85 m/s^2
F=ma
F=600*1.85
F=1110N
Therefore, F=1110N
Answer:
D. 0.9
Explanation:
Calculating minimum coefficient of static friction, we first resolve the forces (normal and frictional) acting on the vehicle at an angle to the horizontal into their x and y components. After this, we can now substitute the values of x and y components into equation of static friction. Diagrammatic illustration is attached.
Resolving into x component:
∑
------(1)
Resolving into y component:
∑
------(2)
Static frictional force,
μ
------(3)
substituting
from equation (1) and
from equation (2) into equation (3)
μ
μ
μ 
μ 
The angle the vehicles make with the horizontal α = 42°
μ ≥ tan 42°
μ ≥ 0.9
Explanation:
Now, looking down the solenoid tube determine what direction is the winding. If clockwise in relation to the positive wire then is the south pole, if anti-clockwise then is the north pole. So, to summarize the magnetic south pole is always clockwise in relation to the positive wire.