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Serggg [28]
4 years ago
16

Which polynomial expression represents a sum of cubes?

Mathematics
2 answers:
hram777 [196]4 years ago
6 0

Answer:

Step-by-step explanation:

ITS C

Annette [7]4 years ago
4 0

Answer:

(6 + s)(s2 – 6s + 36)

Step-by-step explanation:

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Help me with 1,2,3 pls thx
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3 years ago
A square fits exactly inside a circle with each of the vertices being on the circumference of the circle. The square has sides l
NNADVOKAT [17]

Answer: The value of x is 5.970.

Step-by-step explanation:

Given: The square has sides length of X cm.

Let r be the radius of the circle.

The square fits exactly inside a circle with each of the vertices being on the circumference of the circle.

Then diagonal of square = diameter of circle

i.e. \sqrt{2}x= 2r    [Diagonal of square = \sqrt{2}(side)]

i.e. r=\dfrac{x}{\sqrt{2}}

area of circle =\pi r^2

i.e. 56=\frac{22}{7}(\frac{x}{\sqrt{2}})^2

56=\frac{22}{7}\times\frac{x^2}{2}\\\\\Rightarrow\ x^2= \dfrac{7}{11}\times56\\\\\Rightarrow\ x^2=35.636\\\\\Rightarrow\ x=\sqrt{35.636}\approx5.970

Hence, the value of x is 5.970.

4 0
3 years ago
Pat has 3 rows of shells. There are 4 shells in esch row. how many shells does pat have?
vazorg [7]

Answer:

The answer is 12

Step-by-step explanation:


3 0
3 years ago
‼️HELP FAST‼️<br> What are the zeros of this function?
nika2105 [10]

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C

Step-by-step explanation:

6 0
4 years ago
Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN
sashaice [31]

Answer:

The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

 and (x2 , y2) are x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

 N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}

∵ y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}

∴ The coordinates of the midpoint are (-2\frac{1}{2},4\frac{1}{2})

* The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

8 0
3 years ago
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