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DENIUS [597]
3 years ago
6

What’s 6.5 inches times 4?

Mathematics
2 answers:
wolverine [178]3 years ago
8 0

Answer:

your answer is 26 inches

AysviL [449]3 years ago
6 0
Hello, the ANWSER to this question is simply 26, explanation the calculator <3 I hope this helps ! Have a nice day
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Esther's company has been contracted to lay carpet in a room at a new observatory. The floor plan for the room is in the shape o
timofeeve [1]

Answer:

  • 3960 ft²

Step-by-step explanation:

The pentagon has been split into 5 congruent triangles.

<u>Each triangle has area of:</u>

  • 1/2*48*\sqrt{40.8^2 - (48/2)^2} = 24*\sqrt{1088.64} = 24*33 = 792 ft²

<u>The area of the room is:</u>

  • 792*5 = 3960 ft²

5 0
3 years ago
I need help relearning inequalities
Leto [7]
This is an example of how you solve an inequality.

7 0
3 years ago
Find a number that is between 2/7 and 4/11 .
Furkat [3]
To answer this problem, one way is to use the calculator and add directly the two numbers and get the average between the two. The answer is 25/77. We can also get this number by getting the LCM of the denominators which is 77. 2/7 is equal to 22/77 while 4/11 is equal to 28/77. 0.5*(22 +28) is equal to 25. Hence the answer is 25/77. 
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3 years ago
What whole number best approximates the value of x?
ivanzaharov [21]

The answer is 87

For this problem, the method I used was more of a guess and check because I simply plugged the options into a calculator to see which one would be closest a little bit past 9.3 but not all the way 9.4

the square root of 87 is 9.32 so you would round down while the square root of 88 is 9.38 which would round up

Hope this helps :)

4 0
3 years ago
Suppose you roll not die. Find the Probability of not rolling an even number
irina [24]
I think you mean roll a die. To do this you would find the number of non-even numbers and divide that number by the total amount of numbers on the die. On a normal six-sided die these numbers would be 1,3,and 5, so your probability of not rolling an even number would be 50%
7 0
3 years ago
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