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Lana71 [14]
3 years ago
7

A tractor trailer's maximum load is 32,000 pounds. If it is already carrying a forklift that weighs 8,200 pounds, how many 250-p

ound palettes of sod can it legally carry in one trip? (solve with an inequality and show work please)
Mathematics
1 answer:
mina [271]3 years ago
8 0
32000-8200=23800pounds
23800/250=95



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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
At 2:00 pm there are 350 freshmen and 200 sophomores at a school carnival. After 2:00 pm 20 freshman leave every hour and 35 sop
dmitriy555 [2]

Answer:

160:340

Step-by-step explanation:

The hours between 2:00pm and 4:00pm is 2 hours. If originally 350 freshman and 200 sophomores are at the carnival, and 20 freshman leave every hour, we can determine how many freshman left in 2 hours:

=20\cdot{2}=40

and if 35 sophomores arrive every half our, we know that for every two hours there is 4 half hours, therefore:

=35\cdot{4}=140

The amount of freshman at 4:00pm:

200-40=160

and the amount of sophomores:

200+140=340

the ratio is 160:340

5 0
3 years ago
Read 2 more answers
Identify the coefficients in the expression below.<br><br> -6x+5y+4x+9
Montano1993 [528]

Answer:

3 coefficients in this expression are: -2x, 5y and 9 (natural number)

Step-by-step explanation:

-6x + 5y + 4x + 9

= -6x + 4x + 5y + 9

= -2x + 5y + 9

3 coefficients in this expression are: -2x, 5y and 9 (natural number)

Hope this help you :3

5 0
3 years ago
Read 2 more answers
Find the area of ABC
shutvik [7]

Answer:

24 ft sq.

Step-by-step explanation:

formula for area of triangle is: bh/2

8(6)/2 = area

48/2 = area

24 = area

6 0
3 years ago
I need help please it would really help
Softa [21]

Answer:

B

Step-by-step explanation:

V = 4/3 * radius^3 * pi = 4/3 * 4^3 * pi = 256 /3 * pi

7 0
3 years ago
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