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3 years ago

What is the answer to 3/8 + 4/5 ?

Mathematics

2 answers:

REY [17]3 years ago

6 0

find the lcm first for 8 and 5 which is 40

closs multiply the 4 given numbers

so,

8x4 +5x3/ 40 (lcm)

32+15/40 = 47/40

47/40 = 1.175

ans = 1.175

hope that helps u out

Phantasy [73]3 years ago

6 0

$\frac{3}{8}+ \frac{4}{5} \\ 
 \\ \frac{3*5}{8*5}= \frac{15}{40} \\ 
 \\ \frac{4*8}{5*8}= \frac{32}{40} \\ 
 \\ \frac{15}{40}+ \frac{32}{40}= \frac{47}{40} \\ 
 \\ \frac{47}{40}=1 \frac{7}{40} \\ 
 \\ Answer:1 \frac{7}{40} \\$

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Step-by-step explanation:

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A. $y'=(3\sin x)'=3\cos x$ . Differentiate again to get $y''=(3\cos x)'=-3\sin x$ , then $y''+y=-3\sin x+3\sin x=0\neq 3\sin x$ so this choice of y doesn't solve the equation.

B. $y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x$ and $y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x$ , then $y''+y=10\sin x+6\cos x\neq 3\sin x$ so y is not a solution

C. $y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x$ hence $y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x$ . Then $y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x$ so y is a solution.

D. $y'=-3\sin x$ and $y''=-3\cos x$ , then $y''+y=0$ thus y isn't a solution

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