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3 years ago

Why is the enzyme pectinase added during the manufacture of fruit juices?

1 answer:

6 0

The choices can be found elsewhere and as follows:

A.The enzyme pectinase speeds up the breakdown of pectin in fruits, producing more juice.. .
B.The enzyme pectinase enhances the taste of fruit juices, making them more popular.. .
C.The enzyme pectinase speeds up the breakdown of toxins in fruits, producing more juice.

The correct answer would be A. The enzyme pectinase speeds up the breakdown of pectin in fruits, producing more juice. With this, the manufacturer company will get more volume of product from same amount of resource.

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C3H8(g) + 5O2(g) ⟶ 3CO2(g) + 4H2O(g) H = -2220 kJ If 865.9 g of H2O is produced during this combustion, how much heat is generat

dem82 [27]

Answer:

3 × 10⁴ kJ

Explanation:

Step 1: Write the balanced thermochemical equation

C₃H₈(g) + 5 O₂(g) ⟶ 3 CO₂(g) + 4 H₂O(g) ΔH = -2220 kJ

Step 2: Calculate the moles corresponding to 865.9 g of H₂O

The molar mass of H₂O is 18.02 g/mol.

865.9 g × 1 mol/18.02 g = 48.05 mol

Step 3: Calculate the heat produced when 48.05 moles of H₂O are produced

According to the thermochemical equation, 2220 kJ of heat are evolved when 4 moles of H₂O are produced.

48.05 mol × 2220 kJ/4 mol = 2.667 × 10⁴ kJ ≈ 3 × 10⁴ kJ

5 0

2 years ago

Use the following vocabulary words in a 3-5 paragraph sentence. Please highlight or bold the words as you use them in your parag

kaheart [24]

Answer:

hey baby leave all and come with me

3 0

3 years ago

You put scruffy can run up to 2 meters/sec on his fastest days scruffy has a mass of 8 KG what is his maximum kinetic energy on

ale4655 [162]

Answer:

E = 16 J

Explanation:

We have,

You put scruffy can run up to 2 m/s on his fastest days scruffy has a mass of 8 kg

It is required to find the maximum kinetic energy on his fastest days. If v is the velocity, then kinetic energy is given by :

$E=\dfrac{1}{2}mv^2$

Plugging all the values,

$E=\dfrac{1}{2}\times 8\times 2^2 \\\\E=16\ J$

So, the maximum kinetic energy on his fastest day is 16 J.

6 0

3 years ago

A 2.0 mol ideal gas system is maintained at a constant volume of 4.0 L. If 100 J of heat is added, what is the work done on the

LuckyWell [14K]

Answer:

Work done on the system is zero , hence no work is done since the process is isochoric. There is no work done if the volume remains unchanged. (Though the temperature rises, work is only accomplished when the volume of the gas changes.)

Explanation:

ISOCHORIC PROCESS - An isochoric process, also known as a constant-volume process, isovolumetric process, or isometric process, is a thermodynamic process in which the volume of the closed system undergoing the process remains constant through the process. The heating or cooling of the contents of a sealed, inelastic container is an example of an isochoric process. The thermodynamic process is the addition or removal of heat, the closed system is established by the isolation of the contents of the container, and the constant-volume condition is imposed by the container's inability to deform. It should be a quasi-static isochoric process in this case.

Hence , the work done in the system is zero.

7 0

2 years ago

How might we create the best possible solution to a problem?

Ray Of Light [21]

Think it though and always go back to the cause of the problem

8 0

2 years ago