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Gala2k [10]
3 years ago
10

1) h2+o2 -> h2o does equation 1 follow the law of conservation of mass? how can you tell?

Chemistry
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

The given equation not following the law of conservation of mass.

Explanation:

H₂ + O₂ →  H₂ O

The number of oxygen atoms on both side of equation are not equal thus mass is not conserved and this equation not follow the this law.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

2H₂ + O₂ →  2H₂ O

there are two oxygen atoms and four hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

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2C2H2 + 5O2 = 4CO2 + 2H2O

After balancing the equation, the reaction ratio between C2H2 and O2 is 2:5.

The moles of O2 in this reaction is 84.0 mol. According to the above ratio, the moles of C2H2 needed to react completely with the O2 is 84.0mole *2/5 = 33.6 mole.
6 0
3 years ago
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To 225 mL of a 0. 80 M solution of Kl, a student adds enough water to make 1. 0 L of a more dilute Kl solution. What is the mola
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Answer: 0.18 M

Explanation:

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Final Molarity, M2 = M1V1/V2

= 0.8 x 225/1000

= 0.18 M

7 0
2 years ago
Calcium oxide and oxygen gas are produced by the thermal decomposition of limestone in the reaction CaCO (s) CaO(s) + CO (g). Wh
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The mass of lime that  can  be produced  from  4.510 Kg of limestone  is calculated  as  below

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by use of mole ratio between CaCO3  to CaO  (1:1) the  moles of CaO  is also= 45.10 moles
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6 0
3 years ago
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The ion MnOis often used to analyze for the Fe2+ content of an aqueous solution by using the (unbalanced) reaction Mno+Fe2+ + Fe
dusya [7]

Answer:

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The first step is to <u>balance the reaction</u> between the Ferrous ion and the permanganate ion:

5~Fe^+^2~+~MnO_4^-^1~+~8H^+~->~5Fe^+^3~+~Mn^+^2~+4H_2O

Then we have to <u>calculate the moles</u> of MnO_4^-:

M~=~\frac{mol}{L}

mol~=~M*L

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0.002088~mol~MnO_4^-\frac{5~mol~Fe^+^2}{1~mol~MnO_4^-}=0.01044~mol~Fe^+^2

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