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3 years ago

1) h2+o2 -> h2o does equation 1 follow the law of conservation of mass? how can you tell?

Chemistry

1 answer:

emmainna [20.7K]3 years ago

6 0

Answer:

The given equation not following the law of conservation of mass.

Explanation:

H₂ + O₂ → H₂ O

The number of oxygen atoms on both side of equation are not equal thus mass is not conserved and this equation not follow the this law.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

2H₂ + O₂ → 2H₂ O

there are two oxygen atoms and four hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

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A sample of Copper absorbs 43.6 KJ of heat, resulting in a temperature rise of 75.0 oC, determine the mass (in Kg) of the copper

yanalaym [24]

Explanation:

here is the answer to your question

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3 years ago

A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr

sergey [27]

Answer:

184.62 ml

Explanation:

Let $p_1, v_1,$ and $T_1$ be the initial and $p_2, v_2,$ and $T_2$ be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

$p_1=p_2$ ...(i)

$v_1$ = 200 ml

$T_1= 26 ^{\circ}C = 273+26 =299$ K

$T_2= 3 ^{\circ}C = 273+3 =276$ K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

$p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)$

For the final condition,

$p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)$

Equating equation (i), and (ii)

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

$\frac{v_1}{T_1}=\frac{v_2}{T_2}$ [from equation (i)]

$v_2=\frac{T_2}{T_1} \times v_1$

Putting all the given values, we have

$v_2=\frac{276}{299} \times 200 = 184.62 \; ml$

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

7 0

3 years ago

How many grams of NaCl are needed to prepare 50.0 grams of 35.0% of salt solution?

nevsk [136]

Answer:

17.5 g

Explanation:

Given data

Mass of solution to be prepared: 50.0 grams

Concentration of the salt solution: 35.0%

The concentration by mass of NaCl in the solution is 35.0%, that is, there are 35.0 grams of sodium chloride per 100 grams of solution. We will use this ratio to find the mass of sodium chloride required to prepare 50.0 grams of a 35.0% salt solution.

$50.0gSolution \times \frac{35.0gNaCl}{100gSolution} = 17.5gNaCl$

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3 years ago

AN atoms nucleus contains it's protons and electrons true or false

lesantik [10]

True, an atoms nucleus has both protons and electrons.

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3 years ago

What is the enthalpy of combustion (per mole) of C4H10 (g)?

Artemon [7]

The balanced chemical reaction for the complete combustion of C4H10 is shown below:

C4H10 + (3/2)O2 --> 4CO2 + 5H2O

The enthalpy of formation are listed below:
C4H10: -2876.9 kJ/mol
O2: none (because it is pure substance)
CO2: -393.5 kJ/mol
H2O: -285.8 kJ/mol

The enthalpy of combustion is computed by subtracting the total enthalpy formation of the reactants from that of the products.

ΔHc = (4)(-393.5 kJ/mol) + (5)(-285.8 kJ/mol) - (-2876.9 kJ/mol)
= -<em>126.1 kJ</em>

Thus, the enthalpy of combustion of the carbon is -126.1 kJ.

5 0

3 years ago

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