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lorasvet [3.4K]
3 years ago
7

When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose anot

her bomb is tested, and 8.7 grams of matter are converted into energy. How many joules of energy are released by the explosion
Chemistry
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

See explanation

Explanation:

Given Einstein's theory of relativity, we have that;

E= mc^2

m= mass of the substance

c= speed of light

For one gram of the substance,

E= 1 ×10^-3 × (3 × 10^8)^2

E = 9 × 10^13 J

For 8.7 g of matter;

E = 8.7 × 10^-3× (3 × 10^8)

E= 7.83 ×10^ 14 J

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Answer:

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At a high temperature, equal concentrations of 0.160 mol/L of H2(g) and I2(g) are initially present in a flask. The H2 and I2 re
Nikitich [7]

Explanation:

The given reaction is as follows.

                                H_{2} + I_{2} \rightarrow 2HI

Initial :                  0.160    0.160          0  

Change :                  -x           -x              2x

Equilibrium:        0.160 - x    0.160 - x       x

It is given that [H_{2}] = [0.160 - x] = 0.036 M

and,                [I_{2}] = [0.160 - x] = 0.036 M      

so,                             x = (0.160 - 0.036) M

                                    = 0.124 M

As, [HI] = 2x.

So,           [HI] = 2 \times 0.124

                       = 0.248 M

As it is known that expression for equilibrium constant is as follows.

               K_{eq} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}

                                  = \frac{(0.248)^{2}}{(0.036)(0.036)}

                                  = 47.46

Thus, we can conclude that the equilibrium constant, Kc, for the given reaction is 47.46.

                               

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3 years ago
Be sure to answer all parts.
Ede4ka [16]

The Ksp of the solution is 1.97 * 10^-9.

<h3>What is the pH?</h3>

The pH is defined as the hydrogen ion concentration of the solution. Now we have the pH of the solution as 10.9.

We know that;

pOH = 14 - pH

pOH = 14 - 10.9

pOH = 3.1

[OH^-] = Antilog [-3.1]

[OH^-] =7.9 * 10^-4 M

Now

Ksp = [M^2+] [2OH^-]^2

Ksp = s * (2s)^2

Ksp = 4s^3

Now s = 7.9 * 10^-4 M

Ksp = 4(7.9 * 10^-4)^3

Ksp = 1.97 * 10^-9

Learn more about Ksp:brainly.com/question/27132799

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Which element can form an oxide with the general formula m2o or mo where m is a metal
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Answer:

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Explanation:

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