I NEED THIS ANSWER FAST !!!! Show work.

Line segment TS is tangent to circle O at point N.

garik1379 [7]

Answer:

148°

Step-by-step explanation:

The measure of the intercepted arc QN is twice the measure of inscribed angle QNT.

arc QN = 2(74°) = 148°

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<em>Comment on the question and answer</em>

Your description "on the circle between points Q and N" is ambiguous. You used the same description for both points P and R. The interpretation we used is shown in the attachment. If point P is on the long arc NQ, then the measure of arc QPN will be the difference between 148° and 360°, hence 212°. You need to choose the answer that matches the diagram you have.

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We call angle QNT an "inscribed angle" because it is a degenerate case of an inscribed angle. The usual case has the vertex of the angle separate from the ends of the arc it intercepts. In the case of a tangent meeting a chord, the vertex is coincident with one of the ends of the intercepted arc. The relation between angle measure and arc measure remains the same: 1 : 2.

7 0

3 years ago

-2(6+s) Greater than or equal to -15 - 2s

Eddi Din [679]

Answer:

I'm leaning mostly towards C Because there is a solution, None of them are real numbers and if they were, S would = 5 Especially positive S

~ Zachary

7 0

3 years ago

Can someone please help me? Is the answer 42?

SIZIF [17.4K]

Answer:

X = 46

Step-by-step explanation:

X + 43 + 35 + 56 =180

X + 134 = 180

X = 180 - 134

X = 46

6 0

2 years ago

Robert went to the grocery store and purchased cans of soup and frozen dinners. each can of soup has 300 mg of sodium and each f

Paraphin [41]

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Step-by-step explanation:

Let,

Soup = x

Frozen Dinner = y

According to given statement of sodium;

300x + 500y = 5200 eqn 1

And,

x + y = 14 eqn 2

$Multiplying\ equation\ 2\ with\ 300\\300(x+y=14)\\300x+300y=4200\ Eqn 3\\$

Subtracting Eqn 3 from Eqn 1;

$(300x+500y)-(300x+300y)=5200-4200\\300x+500y-300x-300y=1000\\200y=1000\\y=\frac{1000}{200} \\y=5$

Putting value of y in Eqn 1;

$300x+500(5)=5200\\300x+2500=5200\\\\Subtracting\ 2500\ from\ both\ sides\ \\300x+2500-2500=5200-2500\\300x=2700\\x=\frac{2700}{300} \\x=9$

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Keywords: Variables, linear equations, subtraction.

Learn more about linear equations at;

#LearnwithBrainly

5 0

2 years ago

Suppose y varies inversely with x, and y = a when x = a 2. What inverse variation equation relates x and y ?

Sphinxa [80]

The variation equation is xy = a^3

<h3>How to determine the equation?</h3>

An inverse variation is represented as:

xy = k

Where k is the constant of variation

When y = a and x =a^2, we have:

k = a * a^2

Evaluate

k = a^3

Substitute k = a^3 in xy = k

xy = a^3

Hence, the equation is xy = a^3