Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
10
Step-by-step explanation:
Answer:
y = 2x^2 − 4x + 5
y = 2(x^2 − 2x) + 5
y = 2(x^2 − 2x + 1 - 1) + 5
y = 2(x^2 − 2x + 1) + 5 - 2
y = 2(x - 1)^2 + 3
x = 1 is the axis of symmetry.
Do you agree?
GIVE BRANLIEST LOOK AT IMAGE THE ANSWER IS ON THAT IMAGE TRUST ME
Step-by-step explanation:
Answer:
59m
Step-by-step explanation:
No of passenger cars in the train = 6
length of each passenger cars = 18m
total length of 6 passenger cars = 18 * 6 = 108 m
length of caboose = 10m
total length of train when caboose is included = 108 m + 10 m = 118m
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Let the length of truck be X m
given that length of train is twice of length of truck = 2*X
but length of train as found above is 118 m
this implies
2X = 118
X = 118/2 = 59m
Therefore length of truck is 59m
