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Marysya12 [62]
4 years ago
6

A 52.8-g sample of glucose (a nondissociated, nonvolatile solute with the formula C6H12O6) is dissolved in 158.0 g of water. Wha

t is the vapor pressure of this solution at 100°C?
Chemistry
1 answer:
LUCKY_DIMON [66]4 years ago
7 0
Calculate  the  mole  of  glucose  and  water
 The  moles  of water =158g/18g/mol=8.778 moles
moles of  glucose =52.8g/180g/mol=0.293 moles
determine  the mole  fraction  of  the  solvent
that  is   x solvent = 8.778/ (8.778+0.293)=0.9677
use  the  Raults  law  to  determine  the  vapor  pressure
100  degree  of  water  has   a  vapor  pressure  of  760 mmhg
p solution=(x  solvent) (p^o solvent)
p solution=0.9677 x760 =735.45 mmHg

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Answer: Option (E) is the correct answer.

Explanation:

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Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ C_3H_7 NO_3}{89.1 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

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= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

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\mathbf {i = 1.51 }

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