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tresset_1 [31]
3 years ago
11

Which of the following conditions will result in a reaction that is spontaneous only at high temperatures?

Chemistry
1 answer:
Korolek [52]3 years ago
6 0
You have to use the equation ΔG=ΔH-TΔS.
With that equation you know that a reaction with a positive change in enthalpy and positive change in entropy will only be spontaneous at high temperatures since ΔG needs to be negative for a reaction to be spontaneous.

I hopet this helps.  Let me know if anything is unclear.
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Based on the tiles shown, how many moles of oxygen gas (o2) are needed to produce 36.04 grams of water (h2o) when reacting with
madreJ [45]
We calculate for the number of moles of water given its mass by dividing the given mass by the molar mass. 
                               n water = (36.04 g) / (18 g/mol) 
                                n water = 2 mols
From the given balanced equation, every 6 moles of water produced will require 7 moles of oxygen.
                                n oxygen = (2 mols H2O) x (7 moles O2 / 6 moles H2O)
                                n oxygen  = 2.33 mols O2
3 0
3 years ago
WILL NAME BRAINLIEST
Daniel [21]

Answer:

Volume and density are inversely related

3 0
4 years ago
How would i calculate molecules of water produced in a reaction?
levacccp [35]
You would calculate them by dividing them and then multiplying to get the final answer
5 0
4 years ago
What did Ernest Rutherford’s gold foil experiment demonstrate about atoms? Their positive charge is located in a small region th
sergey [27]

Their positive charge is located in a small region that is called the nucleus.

Explanation:

Ernest Rutherford in his gold foil experiment was able to demonstrate that the nucleus is made up of positive charges which occupies a small and tiny nucleus.

Rutherford bombarded a thin gold foil with alpha particles from a radioactive source.

  1. He observed that all the particles passed through but a small portion was deflected back.
  2. This led to his proposition of the nuclear model the atom.

learn more:

Ernest Rutherford brainly.com/question/1859083

#learnwithBrainly

5 0
3 years ago
Calculate the molar mass of Fe2(SO4)3. Then Calculate the mass of iron(III) sulfate of 4.05x10^23 formula units. Work must be sh
Talja [164]

Answer:

Molar mass: 399.9 g/mol

The mass of iron(III) sulfate is 269 grams.

Explanation:

First of all, you have to find the molar mass of Fe2(SO4)3.

So you find the molar first for each element

<h3>Fe = 55.8 amu</h3><h3>S = 32.1 amu</h3><h3>O = 16.0 amu</h3>

However, there are 2 iron atoms, 3 sulfur atoms, and 12 oxygen atoms.(Don't forget the 3 outside the parenthesis of SO4).

So you do this

<h3>55.8(2) + 32.1(3) + 16.0(12) = 399.9 </h3>

So the final answer is 399.9 g/mol

Second of all, if you want to find the mass of Fe2(SO4)3, you have to convert from formula units to moles. After that, then you convert from moles to grams.

If you want to convert from molecules to molecules, you have to use Avogadro's number. Avogadro's number is 6.02 x 10^23. Then if you want to convert from moles to grams, you use the molar mass. We already know that the molar mass is 399.9 g/mol.

Therefore, now use dimensional analysis to show your work.

<h3>(4.05 x 10^23) formula units of Fe2(SO4)3 * 1 mol/ 6.02 x 10^23 formula units * 399.9 g/mol / mol</h3>

Formula units in the beginning and the moles will cancel out.

<h3>So [(4.05 x 10^23) / (6.02 x 10^23)] x 399.9 = 269.0357143</h3>

But we need to use significant figures with the least digits(which is 4.05) So we round to the nearest whole number.

<h3>269.0357143 = 269</h3>

So the final answer for the mass of iron(III) sulfate is 269 grams(don't forget the units).

Hope it helped!

5 0
3 years ago
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