propose a synthetic route for the synthesis of a named alkanal starting with ethyl formate and grignard reagent.
1 answer:
Answer:
See explanation and image attached
Explanation:
A Grignard reagent is an alkyl magnesium halide. If it reacts with ethyl formate, an intermediate is formed as shown.
This intermediate can undergo water hydrolysis to form a diol, ethanol and MgBrOH.
Oxidation of the diol obtained now yields the corresponding alkanal which in this case is ethanal.
The scheme of the reaction is shown in the image attached to this answer.
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<u>Answer:</u> The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
....(1)
- <u>For Iron:</u>
Given mass of iron = 4.31 g
Molar mass of iron = 53.85 g/mol
Putting values in above equation, we get:
For the given chemical reaction:
By Stoichiometry of the reaction:
2 moles of iron produces 2 moles of iron (ii) oxide.
So, 0.0771 moles of iron will produce = of iron (ii) oxide
Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:
Moles of of iron (II) oxide = 0.0771 moles
Molar mass of iron (II) oxide = 71.844 g/mol
Putting values in equation 1, we get:
To calculate the percentage yield of iron (ii) oxide, we use the equation:
Experimental yield of iron (ii) oxide = 5.17 g
Theoretical yield of iron (ii) oxide = 5.53 g
Putting values in above equation, we get:
Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %