If you have $15000 and you earn 10% simple interest per year on it for 10 months how much will you have?

Which could be a conditional relative frequency table? A 4-column table with 3 rows. The first column has no label with entries

kotykmax [81]

Answer:

<u>II. Second table</u>

A B Total

C 0.25 0.75 1.00

D 0.35 0.65 1.00

Total 0.30 0.70 1.00

Explanation:

<h2>Tables</h2>

<u>I. First table </u>

A B Total

C 0.25 0.25 0.50

D 0.25 0.25 0.50

Total 0.50 0.25 1.00

<u>II. Second table</u>

A B Total

C 0.25 0.75 1.00

D 0.35 0.65 1.00

Total 0.30 0.70 1.00

<u>III. Third table</u>

<u></u>

A B Total

C 0.75 0.25 0.50

D 0.25 0.75 0.50

Total 0.50 0.50 1.00

<u>IV. Fourth table</u>

A B Total

C 0.65 0.35 1.00

D 0.35 0.65 1.00

Total 1.00 1.00 1.00

<h2>Solution</h2>

A <em>conditional relative frequency table</em> shows the relative frequencies determined upon a row or column.

There are two types of relative conditional frequency table: 1) row conditional relative frequency, and 2) column conditional relative frequency.

When you divide the joint frequency by the marginal frequency of the column total you have the row conditional frequency table. When you dividethe joint frequency by the row total you have the colum conditional frequency table.

In a row conditional relative frequency each total of the right hand column equals 1. This is the case of the second table.

In a column conditional relative frequency each total of the bottom row equals 1. This is not happening with any of the shown tables.

Hence, only the second table could be a conditional relative frequency table.

5 0

3 years ago

Read 2 more answers

Please help with this question!

ZanzabumX [31]

S > less than or equal to 130
d < greater than or equal to $500

4 0

2 years ago

Read 2 more answers

Need help... on this one plsss help

Scrat [10]

Answer:

A

Step-by-step explanation:

Tiffany should have multiplied by 0.5 in step 1, not divided.

5 0

2 years ago

Read 2 more answers

Find a parametrization of the line in which the planes x + y + z = -6 and y + z = -8 intersect.

rewona [7]

Answer:

L(x,y) = (2,-8,0) + (0,-1,1)*t

Step-by-step explanation:

for the planes

x + y + z = -6 and y + z = -8

the intersection can be found subtracting the equation of the planes

x + y + z - ( y + z ) = -6 - (-8)

x= 2

therefore

x=2

z=z

y= -8 - z

using z as parameter t and the point (2,-8,0) as reference point , then

x= 2

y= -8 - t

z= 0 + t

another way of writing it is

L(x,y) = (2,-8,0) + (0,-1,1)*t

6 0

3 years ago

A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t

Katyanochek1 [597]

The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability) is the opposite of (no car probability) In this case, the easier way is
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability)
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability = (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120

3 0

3 years ago