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netineya [11]
3 years ago
14

You throw a ball straight up in the air trying to throw it as high as possible. What do you think happens to the balls kinetic e

nergy as it rises?
Chemistry
1 answer:
mote1985 [20]3 years ago
6 0
With the info given i would have to say their is no kinetic energy, it's all potential energy.
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1. Complete the balanced dissociation equation for the compound below. If the compound does not dissociate, write NR after the r
puteri [66]

Answer:

1. (NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

2. Al³+ (aq) + PO₄³+ (aq) ----> AlPO₄ (s)

Explanation:

The dissociation of ammonium sulphide, (NH₄)₂S when dissolved in water is given in the equation below:

(NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

However very little S²- ions are present in solution due to the very basic nature of the S²- ion (Kb = 1 x 105).

The ammonium ion being a better proton donor than water, donates a proton to sulphide ion to form hydrosulphide ion which exists in equilibrium with aqueous ammonia.

S²- (aq) + NH₄+ (aq) ⇌ SH- (aq) + NH₃ (aq)

Aqueous solutions of ammonium sulfide are smelly due to the release of hydrogen sulfide and ammonia, hence, their use in making stink bombs.

2. The reaction between aluminium nitrate and sodium phosphatein aqueous solution is a double decomposition reaction whish results in the precipitation of insoluble aluminium phosphate. The equation of the reaction is given below :

Al(NO₃)₃ (aq) + Na₃PO₄ (aq) ----> AlPO₄ (s) + 3 NaNO₃ (aq)

The net ionic equation is given below:

Al³+ (aq) + PO₄³+ (aq) ----> AlPO₄ (s)

7 0
3 years ago
The orbital radius of Venus is 0.72 AU. What is this distance in kilometers? (One AU is about 150 million kilometers.)
Evgen [1.6K]
<span>The answer is D) 108 million kilometers. To solve this problem, you must perform a simple unit conversion calculation. 1 AU = 150,000,000 km is the conversion factor. Take the radius of Venus, .72 AU, and multiply it by 150,000,000 km/1 AU. You flip the conversion factor so that the units of the original distance in the numerator cancel the units in the denominator of the conversion factor. completing the calculation gives you 108,000,000 km</span>
6 0
3 years ago
How many Liters of 0.50M HCl are needed to neutralize 0.050L of 0.101M Ba(OH)2?
Aleksandr-060686 [28]

Answer:

V_{HCl}=5.05x10^{-3}L

Explanation:

Hello,

In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

2*n_{HCl}=n_{Ba(OH)_2}

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L

Besr regards.

8 0
3 years ago
Read 2 more answers
You are throwing a pizza party for 15 people and figure that each person will eat 4 slices. You call the pizza place and learn t
ANEK [815]

Answer:

15 people x 4 slices so you’ll need 60 pieces

60/12(the amount of slices per pizza) =5

You need 5 pizzas. $14.78 x 5 = 73.90.

Explanation:

the answer is that one 73.90 is rounded nearest cent : ) took me a while to get it

8 0
3 years ago
Read 2 more answers
What is the electronic configuration of Au3+?
Anettt [7]

Answer:

AU^{3+} : [Rn] 5f^3

Explanation:

Writing electronic configuration of any element you should know atomic number of that element ,

and also electrons are filling according to their energy level and first electron is filled in the lower energy orbital

and it follows n+1 rule if n+1 is same for two orbital electron will go first in the lowest value of n.

writing electronic configuration of ion can be done like first for their neutral atom and then add or remove electron it will make things easy because there are also some eception case their you may do wrong.

AU : [Rn] 5f^3 6d^1 7s^2

remove three electron from outer most shell of AU

AU^{3+} : [Rn] 5f^3

4 0
3 years ago
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