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madreJ [45]
3 years ago
15

What is the mass percent of each element in water

Chemistry
1 answer:
Vladimir79 [104]3 years ago
5 0

Mass Percent of Hydrogen. To find the mass percent of hydrogen in water, take the molar mass of hydrogen in the water molecule, divide by the total molar mass of water, and multiply by 100. Dividing 2.016 by 18.016 gives you 0.1119. Multiply 0.1119 by 100 to get the answer: 11.19 percent

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Acetaminophen is the generic name of the pain reliever in Tylenol and some other headache remedies- The compoundhas the molecula
slega [8]

<u>Answer:</u> The mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

<u>Explanation:</u>

We are given:

A chemical compound having chemical formula of C_8H_9NO_2. This compound is made by the combination of carbon, hydrogen, nitrogen and oxygen elements.

1 mole of acetaminophen contains 8 moles of carbon atom, 9 moles of hydrogen atom, 1 mole of nitrogen atom and 2 moles of oxygen atom

Mass of carbon element = (8\times 12)=96g/mol

Mass of hydrogen element = (9\times 1)=9g/mol

Mass of nitrogen element = (1\times 14)=14g/mol

Mass of oxygen element = (2\times 16)=32g/mol

Mass of the compound = 151 g/mol

To calculate the percentage composition of an element in a compound, we use the equation:

\%\text{ composition of an element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100      ........(1)

  • <u>For carbon element:</u>

Putting values in equation 1, we get:

\% \text{ composition of carbon element}=\frac{96}{151}\times 100\\\\\% \text{ composition of carbon element}=63.57\%

  • <u>For hydrogen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of hydrogen element}=\frac{9}{151}\times 100\\\\\% \text{ composition of hydrogen element}=5.96\%

  • <u>For nitrogen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of nitrogen element}=\frac{14}{151}\times 100\\\\\% \text{ composition of nitrogen element}=9.28\%

  • <u>For oxygen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of oxygen element}=\frac{32}{151}\times 100\\\\\% \text{ composition of oxygen element}=21.19\%

Hence, the mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

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3 years ago
What is the function of a coromosome
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Chromosomes have genes that determine specific thing about a person (hair color, eye color, how tall or short a person is etc....).


4 0
3 years ago
A closed container holds 2.0 moles of CO2 gas at STP. How many moles of oxygen can be placed in a container of the same size at
PilotLPTM [1.2K]

Answer: 2 moles

Explanation:

STP is Standard Temperature and Pressure. That means the pressure is 1.00 atm and the temperature is 273K. Since the oxygen is placed in the same container, we can use Ideal Gas Law to figure out what container the CO₂ used.

Ideal Gas Law: PV=nRT

P=1.00 atm

n=moles

R=0.08206 Latm/Kmol

T=273K

CO₂

V=\frac{nRT}{P}

V=\frac{(2.0 mol)(0.08206Latm/Kmol)(273K)}{1.00atm}

V=44.8L

Since we know that CO₂ has a 44.8 L container, we can use that to find the moles of oxygen.

n=\frac{PV}{RT}

n=\frac{(1.00atm)(44.8L)}{(0.08206Latm/Kmol)(273K)}

n=1.99=2mol

There are 2 mol of oxygen.

5 0
3 years ago
Hi I need help with these 3 questions asap please and thank you
inn [45]
1 light changes speed as we approach source. 2 in a vacuum 3. In a vacuum
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3 years ago
A mixture initially contains A, B, and C in the following concentrations: [A] = 0.650 M, [B] = 1.35 M, and [C] = 0.300 M. The fo
dimaraw [331]

<u>Answer:</u> The value of K_c for given reaction is 0.465

<u>Explanation:</u>

We are given:

Initial concentration of A = 0.650 M

Initial concentration of B = 1.35 M

Initial concentration of C = 0.300 M

Equilibrium concentration of A = 0.550 M

Equilibrium concentration of B = 0.400 M

For the given chemical equation:

                           A+2B\rightarrow C

<u>Initial:</u>                0.65     1.35     0.30

<u>At eqllm:</u>        0.65-x   1.35-2x   0.30+x

Evaluating the value of 'x'

0.650-x=0.550\\\\x=0.100

So, equilibrium concentration of B = 1.35 - 2x = [1.35 - 2(0.100)] = 1.15 M

Equilibrium concentration of C = (0.30 + x) = (0.300 + 0.100) = 0.400 M

The expression of K_c for above equation follows:

K_c=\frac{[C]}{[A][B]^2}

Putting values in above equation, we get:

K_c=\frac{0.400}{0.650\times (1.15)^2}\\\\K_c=0.465

Hence, the value of K_c for given reaction is 0.465

7 0
3 years ago
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