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Nutka1998 [239]
3 years ago
15

What is the type of reaction for the following: Silver nitrate + aluminum

Chemistry
1 answer:
Maksim231197 [3]3 years ago
6 0
Single replacement ?
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How do the bonds differ in<br> each type?
VashaNatasha [74]

Answer:

Bonds basically differs with each other due to sharing of electrons .

Explanation:

There are majorly three kinds of bonds

1. Ionic bonds which forms due to an element donate an electron to another element completely .

2. covalent bonds which forms with the mutual sharing of electrons b/w two atoms .

3. metallic bonds which forms b/w metals & they share electrons due to electron negativity difference b/w two atoms or elements

7 0
3 years ago
Read 2 more answers
A 4.305-g sample of a nonelectrolyte is dissolved in 105 g of water. the solution freezes at -1.23c. calculate the molar mass of
amid [387]
The answer is 62.00 g/mol. 
Solution: 
Knowing that the freezing point of water is 0°C, temperature change Δt is 
     Δt = 0C - (-1.23°C) = 1.23°C 
Since the van 't Hoff factor i is essentially 1 for non-electrolytes dissolved in water, we calculate for the number of moles x of the compound dissolved from the equation 
     Δt = i Kf m 
     1.23°C = (1) (1.86°C kg mol-1) (x / 0.105 kg) 
     x = 0.069435 mol 
Therefore, the molar mass of the solute is  
     molar mass = 4.305g / 0.069435mol = 62.00 g/mol
6 0
3 years ago
Describe the whole process of Aluminum extraction from bauxite.​
AlekseyPX

Answer:

Extraction of aluminium

Aluminium ore is called bauxite . The bauxite is purified to produce aluminium oxide, a white powder from which aluminium can be extracted. The extraction is done by electrolysis. The ions in the aluminium oxide must be free to move so that electricity can pass through it.

4 0
3 years ago
Read 2 more answers
Calculate the density of CO2 at a pressure of 685.0 torr and 41.0°C . <br> R=0.0821 (L*atm)/(mol *K)
Keith_Richards [23]

T=41+273=314 k

M=(12)+(16×2)=44g/mol

d=PM/RT

d=685×44/0.0821×314

d=1169.15 g/L

5 0
3 years ago
A compound with molecular formula C6H15N exhibits a singlet at d 0.9 ppm (1H), a triplet at 1.10 ppm (3H), a singlet at 1.15 ppm
Triss [41]

Answer:

CH3 - CH2 - NH - C(CH3)3

Explanation:

The 1HNMR is the acronym for Proton nuclear magnetic resonance and it is used in chemistry or Chemical laboratory for the analysis and identification of compounds.

In order to be able to answer the question accurately you have to have the tables containing all the values for chemical shift. The Chemical shift is measured in ppm and it occur due to Resonance frequency variation.

From the table, a singlet at 1.15 ppm (9H) is - C(CH3)3.

A singlet at d 0.9 ppm (1H) shows the presence of a secondary amine group, that is -R2NH group.

A triplet at 1.10 ppm (3H) shows that we have;

CH3- CH2-

A quartet at 2.6 ppm (2H) shows that we have;

-CH2 - CH3.

Therefore, joining all together we have;

CH3 - CH2 - NH - C(CH3)3.

Kindly check attached file for the picture of the structure.

5 0
3 years ago
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