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beks73 [17]
3 years ago
5

What is the value of f? −1/8f−3/4−1/4f=11?

Mathematics
2 answers:
cluponka [151]3 years ago
8 0
I hope this helps you

Ilya [14]3 years ago
6 0

−1/8 f−3/4−1/4 f=11

f=-31 1/3

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Read 2 more answers
If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?
Rina8888 [55]

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

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3 - b = 0

b = 3.

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2b + 3c + 9 = 0

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