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3 years ago

If sin θ = 2 over 7 and tan θ > 0, what is the value of cos θ?

1 answer:

6 0

Sin θ = 2 / 7
tan θ > 0
cos θ = ?

sin θ = opposite / hypotenuse
tan θ = opposite / adjacent
cos θ = adjacent / hypotenuse

short leg = opposite = 2
hypotenuse = 7
long leg = adjacent = ?

adjacent = √(7² - 2²)
adjacent = √(49 - 4)
adjacent = √45
adjacent = √9 * 5
adjacent = 3 √5

cos θ = adjacent / hypotenuse
cos θ = 3√5 / 7

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

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Which system of equations can be used to find the roots of the equation 12 x 3-5x=2 x 2+x+6

kirill [66]

Answer:

Option (a) is correct.

The system of equation becomes

$y=12x^3-5x\\\\ y=2x^2+x+6$

Step-by-step explanation:

Given : Equation $12x^3-5x=2x^2+x+6$

We have to construct a system of equations that can be used to find the roots of the equation $12x^3-5x=2x^2+x+6$

Consider the given equation $12x^3-5x=2x^2+x+6$

To construct a system of equation put both sides of the given equation equal to a same variable.

Let the variable be "y", Then the equation $12x^3-5x=2x^2+x+6$

becomes,

$12x^3-5x=y=2x^2+x+6$

Thus, The system of equation becomes

$y=12x^3-5x\\\\ y=2x^2+x+6$

Option (a) is correct.

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3 years ago

Read 2 more answers

PLEASE HELP 30 POINTS!!!!!!!!!!!!!!!!!!!!!!!

Anettt [7]

Since you know the value of "x", you can plug in the value for "x" in the equation.

[When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.]

For example:

$x^{-2}$ or $\frac{x^{-2}}{1} =\frac{1}{x^2}$

$\frac{1}{y^{-3}} =\frac{y^3}{1}$ or y³

x = -2

f(x) = 9x + 7

f(-2) = 9(-2) + 7 = -18 + 7 = -11

$g(x)=5^x$

$g(-2)=5^{-2}=\frac{1}{5^2}=\frac{1}{25}$ (idk if you should have it as a decimal or a fraction)

x = -1

f(x) = 9x + 7

f(-1) = 9(-1) + 7 = -9 + 7 = -2

$g(x)=5^x$

$g(-1)=5^{-1}=\frac{1}{5}$

x = 0

f(x) = 9x + 7

f(0) = 9(0) + 7 = 7

$g(x)=5^x$

$g(0)=5^0=1$

x = 1

f(x) = 9x + 7

f(1) = 9(1) + 7 = 9 + 7 = 16

$g(x)=5^x$

$g(1)=5^1=5$

x = 2

f(x) = 9x + 7

f(2) = 9(2) + 7 = 18 + 7 = 25

$g(x)=5^x$

$g(2)=5^2=25$

You need to determine the solution of f(x) = g(x)

Since you know f(x) = 9x + 7 and $g(x)=5^x$ , you can plug in (9x + 7) for f(x), and ( $5^x$ ) into g(x)

f(x) = g(x)

$9x+7=5^x$ You can plug in each value of x into the equation

Your answer is x = 2 because when you plug in 2 for x in the equation, you get 25 = 25

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3 years ago