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3 years ago

The graph shows the function g(x) for a restricted domain.

Mathematics

2 answers:

Harman [31]3 years ago

7 0

Answer:

Option 3

g(x) = Negative RootIndex 3 StartRoot x + 4 EndRoot; x greater-than-or-equal-to –4

Step-by-step explanation:

Since the graph starts at x = -4 and towards the right, domain is x 》-4

g(x) = -(x + 4)^⅓

Because,

0 = -(-4 + 4)^⅓

0 = 0

bezimeni [28]3 years ago

5 0

Answer:

f(-3)=g(-3)

Step-by-step explanation:

The graph shows two linear functions that intersect at (-3,-4).

The blue line is f(x).

At the point of intersection:

....eqn1

The blue line is g(x).

At the point of intersection

....eqn2

Equating both equations we get:

The statement that is true regarding the two functions is that:

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Ksivusya [100]

Answer:

fraction 1 over 3 whole squared m2

Step-by-step explanation:

we know that

The area of a square is

$A=b^{2}$

where

b is the length side of a square

In this problem we have

$b=\frac{1}{3}\ m$

substitute

$A=(\frac{1}{3})^{2}$

$A=\frac{1}{9}\ m^{2}$

therefore

The expression that can be used to find the area of the square is

fraction 1 over 3 whole squared m2

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3 years ago

The graph shows how the number of hats in your collection increased since you began collecting 6 months ago. How many hats did y

Talja [164]

Answer:

Step-by-step explanation:

Two hats were collected in the second month (5-3) =2.

8 0

2 years ago

Plz answer quick write an inequality for the word sentence the temperature t is higher than 5°

Katena32 [7]

T>5

Don't forget to follow me and vote brainliest!!!

3 0

3 years ago

Determine if this is a linearly dependent or independent set: (V, V, V ) where syon V = (1,2,2,-1), V = (4,9,9,-4), v = (5,8,9,-

marishachu [46]

Answer:

This is a linearly independent set.

Step-by-step explanation:

We have these following vectors:

$V_{1} = (1,2,2,-1)$

$V_{2} = (4,9,9,-4)$

$V_{3} = (5,8,9,-5)$

In a set of 3 vectors, if one of these vectors can be written as a linear combination of the 2 other vectors, they are linearly dependent. Otherwise, they are linearly independent.

We can verify this by solving the following system:

$xV_{1} + yV_{2} + zV_{3} = (0,0,0,0)$

If the only solution is $(x,y,z) = (0,0,0)$ , they are L.I. Otherwise, they are L.D.

Solution:

$xV_{1} + yV_{2} + zV_{3} = (0,0,0,0)$

$x(1,2,2,-1) + y(4,9,9,-4) + z (5,8,9,-5) = (0,0,0,0)$

We have the following system of equations:

$x + 4y + 5z = 0$

$2x + 9y + 8z = 0$

$2x + 9y + 9z = 0$

$-x -4y - 5z = 0$

I am going to solve this by the row-reduction of the augmented matrix.

This system has the following augmented matrix:

$\left[\begin{array}{cccc}1&4&5&0\\2&9&8&0\\2&9&9&0\\-1&-4&-5&0\end{array}\right]$

To reduce the first row, i am going to make these following operations:

$L_{2} = L_{2} - 2L_{1}$

$L_{3} = L_{3} - 3L_{1}$

$L_{4} = L_{4} + L_{1}$

So the augmented matrix now is:

$\left[\begin{array}{cccc}1&4&5&0\\0&1&-2&0\\0&1&-1&0\\0&0&0&0\end{array}\right]$

Now I reduce the second row, doing:

$L_{3} = L_{3} - L_{2}$

So the matrix is:

$\left[\begin{array}{cccc}1&4&5&0\\0&1&-2&0\\0&0&1&0\\0&0&0&0\end{array}\right]$

Now we can solve the system:

From the third line, we have that

$z = 0$

From the second line:

$y - 2z = 0$

$y - 2(0) = 0$

$y = 0$

From the first line

$x + 4y + 5z = 0$

$x + 4(0) + 5(0) = 0$

$x = 0$

The only solution for this system is $(x,y,z) = (0,0,0)$ . This means that we have a linearly independent set.

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3 years ago

Which situation is best modeled by the expression x – 25? Answer George places x more video games on a shelf with 25 games. Sara

ryzh [129]

Ahhhhhh im not sure. sorry

3 0

3 years ago