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sertanlavr [38]
3 years ago
10

The graph shows the function g(x) for a restricted domain.

Mathematics
2 answers:
Harman [31]3 years ago
7 0

Answer:

Option 3

g(x) = Negative RootIndex 3 StartRoot x + 4 EndRoot; x greater-than-or-equal-to –4

Step-by-step explanation:

Since the graph starts at x = -4 and towards the right, domain is x 》-4

g(x) = -(x + 4)^⅓

Because,

0 = -(-4 + 4)^⅓

0 = 0

bezimeni [28]3 years ago
5 0

Answer:

f(-3)=g(-3)

Step-by-step explanation:

The graph shows two linear functions that intersect at (-3,-4).

The blue line is f(x).

At the point of intersection:

....eqn1

The blue line is g(x).

At the point of intersection

....eqn2

Equating both equations we get:

The statement that is true regarding the two functions is that:

HOPE THIs HELPS

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If an impulse travels 100 m/s, about how long will it take the impulse to travel 10 meters?
PtichkaEL [24]

Answer:

0.1 seconds

Step-by-step explanation:

10/100=0.1

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Given 2x^2=-8, x is<br><br> A.-2<br> B. 2<br> C. 2i or -2i<br> D. 4i or -4i
Lera25 [3.4K]

Answer:

2i or -2i

Step-by-step explanation:

2x² = -8     First, clear x.

x² = -8/2    Solve

x² = -4        Now, eliminate the square of x by solving the square root of -4.

x = √-4

x = 2i or -2i Is an imaginary number.

4 0
3 years ago
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PLEASE HELP!!!
diamong [38]
DE. AB, is going up BC, isn't decreasing or increasing. CD, isn't decreasing or increasing. Therefore your answer is DE.
8 0
3 years ago
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Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.
svp [43]

Answer:

There will be 20 914 rupees in the amount at the end of 3 years.

Step-by-step explanation:

The amount of rupes after t years in compound interest is given by:

A(t) = A(0)(1+r)^{t}

In which A(0) is the initial amount and r is the interest rate, as a decimal.

Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.

This means that A(0) = 20000, r = 0.015. So

A(t) = A(0)(1+r)^{t}

A(t) = 20000(1+0.015)^{t}

A(t) = 20000(1.015)^{t}

Work out the total amount of money in the account at the end of 3 years.

This is A(3). So

A(3) = 20000(1.015)^{3} = 20913.6

Rounding to the nearest rupee.

There will be 20 914 rupees in the amount at the end of 3 years.

8 0
2 years ago
A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti
prohojiy [21]

ANSWER

Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

To proof

let us assume that the fluid should be drained and replaced with pure antifreeze be x .

As given

A radiator contains 10 quarts of fluid, 30% of which is antifreeze.

Now write 30% in the decimal form

= \frac{30}{100}

Now write 60% in the decimal form

= \frac{60}{100}

After  drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )

The quantity of  antifreeze is

= \frac{30\times (10 - x)}{100}

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

than the equation becomes

= x + \frac{30\times ( 10 - x )}{100} = \frac{60\times10}{100}

solyving

100x +300 - 30x = 600

70x = 300

x = \frac{300}{70}

x = 4.28 quarts (approx)

Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

Therefore the option (c.) is correct .

3 0
3 years ago
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