Answer:
Step-by-step explanation:
Given
Rotation = +270 degrees
Required
Determine the new coordinates of Q (i.e. Q')
When a point (x,y) is rotated +270° about the origin, the new coordinates is: (y,−x)
So:
Where:
and 
Q' will be:
Answer:
<em>m </em>=<em> </em>1/2
Step-by-step explanation:
Use two points on the line given.
(0 , 2) & (-4 , 0)
You are solving for the slope. The slope formula:
<em>m</em> (slope) = (y₂ - y₁)/(x₂ - x₁)
Let:
(x₁ , y₁) = (-4 , 0)
(x₂ , y₂) = (0 , 2)
Plug in the corresponding numbers to the corresponding variables:
<em>m</em> = (2 - 0)/(0 - (-4))
Simplify:
<em>m</em> = (2)/( 0 - (-4))
<em>m</em> = (2)/(0 + 4)
<em>m</em> = 2/4
Simplify the slope. Divide the common factor 2 from both the numerator and denominator:
<em>m</em> = (2/4)/(2/2) = 1/2
1/2 is your slope.
~
(85/86)*688 cg = 680 cg . . . inert ingredient
.. 688 cg -680 cg = 8 cg . . . .active ingredient
Answer:
17.5
Step-by-step explanation:
You know that the sum of the interior angles in a triangle is 180
we will add all the angles,
(x+8)+(2x-8)+(3x-12)=180
x+8+2x-8+3x-12=180 8 and -8 cancel out
6x-12=180
6x=180+12
6x=192
x=192/6=32
x=32
